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16 Dec 2020, 04:30
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
91% (01:11) correct
9%
(01:29)
wrong
based on 97
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A bag of marbles contains twice as many red marbles as blue marbles, and twice as many blue marbles as green marbles. If these are the only colors of marbles in the bag, what is the probability of randomly picking a blue marble from the bag?
(A) 1/6
(B) 2/9
(C) 1/4
(D) 2/7
(E) 1/3
(A) 1/6
(B) 2/9
(C) 1/4
(D) 2/7
(E) 1/3
16 Dec 2020, 07:03
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Bunuel
Let the number of green marbles = x, then the number of Blue marbles = 2x and the number of Red marbles = 4x
Total Marbles = x + 2x+ 4x = 7x
Probability = Favorable outcomes / Total Outcomes = 2x / 7x = 2/7
Option D
Arun Kumar
16 Dec 2020, 10:10
Kudos
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The bag contains two times the red marbles as blue ones. So, R=2B. It also contains two times the blue marbles as green ones. So, B=2G. So if we consider, G to be 2, we get B as 4 and R as 8.
Now the total outcomes: 14. Chances of getting blue: 4. Hence probability of getting blue: 4/14 = 2/7.
Hence, D is the answer.
Posted from my mobile device
Now the total outcomes: 14. Chances of getting blue: 4. Hence probability of getting blue: 4/14 = 2/7.
Hence, D is the answer.
Posted from my mobile device
