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07 Sep 2021, 04:00
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D
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Difficulty:
65%
(hard)
Question Stats:
59% (02:06) correct
41%
(02:07)
wrong
based on 323
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A bar above a digit in a decimal indicates an infinitely repeating decimal. \(333,333.\overline {3}*(10^{–3} – 10^{–5})\) =
A. \(3,333.\overline {3}\)
B. \(3,330\)
C. \(333.\overline {3}\)
D. \(330\)
E. \(0\)
A. \(3,333.\overline {3}\)
B. \(3,330\)
C. \(333.\overline {3}\)
D. \(330\)
E. \(0\)
yashikaaggarwal
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15 Sep 2021, 10:20
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Simply solve bracket.
(10^-3-10^-5)
= (99/100,000)
Now,
=> 333,333.33*99/100,000
=> 333.33*99
Which is surely slightly less than 333.33
Hence
D is the approximate answer.
Posted from my mobile device
(10^-3-10^-5)
= (99/100,000)
Now,
=> 333,333.33*99/100,000
=> 333.33*99
Which is surely slightly less than 333.33
Hence
D is the approximate answer.
Posted from my mobile device
15 Sep 2021, 13:04
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Bunuel
A bar above a digit in a decimal indicates an infinitely repeating decimal. \(333,333.\overline {3}*(10^{–3} – 10^{–5})\) =
A. \(3,333.\overline {3}\)
B. \(3,330\)
C. \(333.\overline {3}\)
D. \(330\)
E. \(0\)
A. \(3,333.\overline {3}\)
B. \(3,330\)
C. \(333.\overline {3}\)
D. \(330\)
E. \(0\)
Key properties:
Multiplying number K by \(10^n\) (where n is positive) moves the decimal place to the RIGHT n spaces.
Multiplying number K by \(10^{-n}\) (where n is positive) moves the decimal place to the LEFT n spaces.
Some examples:
\(1234.567 * 10^{-2} = 12.34567\)
\(123456.7 * 10^{-5} = 1.234567\)
\(8,888,888.\overline {8} * 10^{-4} = 888.\overline {8}\)
Now onto the question!!
We get: \(333,333.\overline {3}*(10^{–3} – 10^{–5}) = 333.\overline {3} - 3.\overline {3}=330\)
Answer: D
