Bunuel
A bath can be filled by the cold water pipe in 10 min and by hot water pipe in 15 min (independently each). A person leaves the bathroom after turning on both pipes simultaneously and returns at the moments when the bath should be full. Finding, however, that the waste pipe has been open he now closes it. In 4 min more, bath is full. In what time would be the waste pipe empty it?
A. 9 min
B. 12 min
C. 14 min
D. 15 min
E. 16 min
Work done by the cold water pipe in 1 minute = \(\frac{1}{10}\)
Work done by the cold water pipe in 1 minute = \(\frac{1}{15}\)
Work done together in 1 minute = \(\frac{1}{10} + \frac{1}{15} = \frac{1}{6}\)
Time taken to fill when both are open = 6 minutes
He returns at the time when the bath should have been full, means that he returns in 6 minutes but finds that the waste pipe also has been opened for 6 minutes.
After he closes the waste pipe, it takes 4 more minutes to fill the tub.
Let the waste pipe empty the bath in x minutes.
Work done by cold pipe in 10 minutes (6 + 4) = \(\frac{10}{10}\) = 1
Work done by Hot pipe in 10 minutes = \(\frac{10}{15} = \frac{2}{3}\)
Work done by waste pipe in 6 minutes = \(\frac{6}{x}\)
Sum of fractions of work done by each = 1
\(1 + \frac{2}{3} + \frac{6}{x} = 1\)
\(\frac{2}{3} = \frac{6}{x}\)
x = 9 minutes
Option AArun Kumar