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A biker increased his average speed by 10 miles per hour in each succe

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A biker increased his average speed by 10 miles per hour in each succe  [#permalink]

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New post 26 Sep 2018, 05:04
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Difficulty:

  15% (low)

Question Stats:

83% (01:44) correct 17% (01:58) wrong based on 50 sessions

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A biker increased his average speed by 10 miles per hour in each successive 10-minute interval after the first interval. If in the first 10-minute interval, his average speed was 30 miles per hour, how many miles did he travel in the fourth 10-minute interval?

(A) 4
(B) 5
(C) 8
(D) 10
(E) 15

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A biker increased his average speed by 10 miles per hour in each succe  [#permalink]

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New post 29 Sep 2018, 12:48
Question asks us to find distance. Since Time and speed is given so \(Distance = Speed x Time\)

Time is giving in min…. convert Time to hour to make it uniform so time becomes \(10/60 = 1/6 hour\)

Distance at First interval \(= Speed*time = 30*1/6\)
Distance at Second interval \(= Speed*time = 40*1/6\)
Distance at Third interval \(= Speed*time = 50*1/6\)

Distance at Fourth interval\(= Speed*time = 60*1/6=10\) Ans D
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A biker increased his average speed by 10 miles per hour in each succe  [#permalink]

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New post 29 Sep 2018, 21:25
Bunuel wrote:
A biker increased his average speed by 10 miles per hour in each successive 10-minute interval after the first interval. If in the first 10-minute interval, his average speed was 30 miles per hour, how many miles did he travel in the fourth 10-minute interval?

(A) 4
(B) 5
(C) 8
(D) 10
(E) 15

A biker increases his average speed by 10 mph for each successive interval.
Speed is 30 mph during the first interval

Speed during 4th interval?

1st-> 2nd-> 3rd--> 4th
30 --> 40 --> 50 -> 60 mph

1 hour = 60 minutes
A speed of \(\frac{60mi}{1hour}=\frac{60mi}{60min}\)

Miles traveled in 4th interval? (r*t) = D
t = 10 minutes (each interval is 10 minutes)

Miles traveled: \((\frac{60mi}{60mins}* 10 mins)=\frac{60}{6}mi=10\) miles

Answer D
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A biker increased his average speed by 10 miles per hour in each succe   [#permalink] 29 Sep 2018, 21:25
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