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A brown flask contains a concoction that is 20% alcohol. A red flask
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22 Feb 2022, 06:00
22 Feb 2022, 06:00
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Question Stats:
70% (02:11) correct
30%
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A brown flask contains a concoction that is 20% alcohol. A red flask contains a concoction with an unknown amount of alcohol. An equal amount of both flasks is poured into an empty jug. If the resulting mixture has an alcohol concentration that is 30% greater than the alcohol concentration of the brown flask, what percent alcohol did the red flask originally contain?
(A) 23%
(B) 25%
(C) 32%
(D) 33%
(E) 40%
Are You Up For the Challenge: 700 Level Questions
(A) 23%
(B) 25%
(C) 32%
(D) 33%
(E) 40%
Are You Up For the Challenge: 700 Level Questions
Re: A brown flask contains a concoction that is 20% alcohol. A red flask
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22 Feb 2022, 07:32
22 Feb 2022, 07:32
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The resulting mixture will have \(20*1.3 = 26\)
As we are mixing both mixtures equally, the average of the two will be 26%.
Let the alcohol content is the red flask be x.
\(\frac{20+x}{2} = 26\)
\(20 + x = 52\)
\(x = 32\)
Answer C
As we are mixing both mixtures equally, the average of the two will be 26%.
Let the alcohol content is the red flask be x.
\(\frac{20+x}{2} = 26\)
\(20 + x = 52\)
\(x = 32\)
Answer C
A brown flask contains a concoction that is 20% alcohol. A red flask
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22 Feb 2022, 14:17
22 Feb 2022, 14:17
1
Kudos
A nice trap option would've been 80 because that's what I set out to look for after a quick skim through of the question, and I believe many might commit the same error 
However, a detailed examination revealed that the final mixture is 30% more concentrated than the one in brown flask. Note that it is 30% and not 30 % points.
So if the brown flask has a 20% strong solution, the final mixture will be 20*1.3=26% strong.
And since we're mixing equal quantities of the brown flask and the red flask, 26 must be the average of 20 and x where x is the strength of the solution in red flask and equals 32.
Hence, option C.
Posted from my mobile device
However, a detailed examination revealed that the final mixture is 30% more concentrated than the one in brown flask. Note that it is 30% and not 30 % points.
So if the brown flask has a 20% strong solution, the final mixture will be 20*1.3=26% strong.
And since we're mixing equal quantities of the brown flask and the red flask, 26 must be the average of 20 and x where x is the strength of the solution in red flask and equals 32.
Hence, option C.
Posted from my mobile device
