It is currently 13 Dec 2017, 09:11

Decision(s) Day!:

CHAT Rooms | Ross R1 | Kellogg R1 | Darden R1 | Tepper R1


Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

A car dealership has 8 cars in stock each having a diferent

  post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
Director
Director
avatar
Joined: 17 Oct 2005
Posts: 921

Kudos [?]: 282 [0], given: 0

A car dealership has 8 cars in stock each having a diferent [#permalink]

Show Tags

New post 21 Feb 2006, 16:09
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A car dealership has 8 cars in stock each having a diferent price. A customer wants to buy 3 cars. What is the probability that the 2 most expensive cars will be selected?

Kudos [?]: 282 [0], given: 0

VP
VP
User avatar
Joined: 29 Dec 2005
Posts: 1337

Kudos [?]: 70 [0], given: 0

Re: combo/prob [#permalink]

Show Tags

New post 21 Feb 2006, 17:54
= 6/8c3=6/56=3/28

Kudos [?]: 70 [0], given: 0

GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 07 Jul 2004
Posts: 5032

Kudos [?]: 457 [0], given: 0

Location: Singapore
 [#permalink]

Show Tags

New post 21 Feb 2006, 19:13
Since each has a different car, assume that the two most expensive has been selected. Now we need to select 1 car out of the remaining 6. - 6C1 = 6 ways

Total number of ways to pick 3 cars from 8 = 8C3 = 56

P = 6/56 = 3/28

Kudos [?]: 457 [0], given: 0

CEO
CEO
User avatar
Joined: 20 Nov 2005
Posts: 2892

Kudos [?]: 337 [0], given: 0

Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
 [#permalink]

Show Tags

New post 21 Feb 2006, 19:16
Total cases of selecting 3 cars = 8C3 = 56

Lets assume 7 and 8 number cars are most expensive. Then in how many combinations of 3 selected cars, 7 and 8 will be there = 6

(1,7,8), (2,7,8).... (6,7,8)

So prob = 6/56 = 3/28
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Kudos [?]: 337 [0], given: 0

Senior Manager
Senior Manager
User avatar
Joined: 11 Jan 2006
Posts: 266

Kudos [?]: 4 [0], given: 0

Location: Chennai,India
 [#permalink]

Show Tags

New post 21 Feb 2006, 21:05
ps_dahiya wrote:
Total cases of selecting 3 cars = 8C3 = 56

Lets assume 7 and 8 number cars are most expensive. Then in how many combinations of 3 selected cars, 7 and 8 will be there = 6

(1,7,8), (2,7,8).... (6,7,8)

So prob = 6/56 = 3/28



thnks got it.. :)
_________________

vazlkaiye porkalam vazltuthan parkanum.... porkalam maralam porkalthan maruma

Kudos [?]: 4 [0], given: 0

  [#permalink] 21 Feb 2006, 21:05
Display posts from previous: Sort by

A car dealership has 8 cars in stock each having a diferent

  post reply Question banks Downloads My Bookmarks Reviews Important topics  

Moderator: chetan2u



GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.