petu wrote:
A car ferry can hold up to 50 tons of cargo. What is the greatest number of vehicles that the ferry can carry if half the vehicles are cars with an average (arithmetic mean) weight of 0.75 tons and half of the vehicles are trucks with an average (arithmetic mean) weight of 5 tons?
A. 10
B. 14
C. 15
D. 16
E. 17
Could someone walk me through please?
This is a Wrong Question. Please Read CAREFULLY the Question Stem.
A car ferry can hold up to 50 tons of cargo. What is the
greatest number of vehicles that the ferry can carry
if half the vehicles are cars with an average (arithmetic mean) weight of 0.75 tons
and half of the vehicles are trucks with an average (arithmetic mean) weight of 5 tons?
Question: What Exactly do you want me to do??
Answer: Find the
greatest number of vehiclesBut Question has already given the constraint (Half of the vehicles are Cars and half of them are Trucks) because of which Maximum Number of Vehicles cannot be found.
Question should be changed to
A car ferry can hold up to 50 tons of cargo. What is the
greatest number of vehicles
that on the ferry
can carry if half the vehicles are cars with an average (arithmetic mean) weight of 0.75 tons and half of the vehicles are trucks with an average (arithmetic mean) weight of 5 tons?
Otherwise, Answer 16 is the wrong one.
Here is the reason.
If there are 16 Vehicles, half of which are Cars and the rest Trucks, then
Total weight of 16 Vehicles = 8*0.75 + 8*5 = 6 + 40 = 46.To load up the ferry to its
Maximum Capacity, 4 More Cars can be loaded on it, making the Total Weight = 46 + 4*0.75 = 46 + 3 = 49 Tons
Therefore, Total Number of Vehicles = 16 + 4 = 20 => 12 Cars and 8 Trucks => Breaks the condition that half the vehicles are Cars and Rest are Trucks. _________________
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