GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 18 Dec 2018, 07:36

# Expecting Soon:

R1 Admission Decisions from McCombs - Join Chat Room for Latest Updates

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

## Events & Promotions

###### Events & Promotions in December
PrevNext
SuMoTuWeThFrSa
2526272829301
2345678
9101112131415
16171819202122
23242526272829
303112345
Open Detailed Calendar
• ### Happy Christmas 20% Sale! Math Revolution All-In-One Products!

December 20, 2018

December 20, 2018

10:00 PM PST

11:00 PM PST

This is the most inexpensive and attractive price in the market. Get the course now!
• ### Key Strategies to Master GMAT SC

December 22, 2018

December 22, 2018

07:00 AM PST

09:00 AM PST

Attend this webinar to learn how to leverage Meaning and Logic to solve the most challenging Sentence Correction Questions.

# A car starts from X and moves towards Y. At the same time

Author Message
TAGS:

### Hide Tags

Director
Joined: 17 Dec 2012
Posts: 629
Location: India
A car starts from X and moves towards Y. At the same time  [#permalink]

### Show Tags

29 Aug 2013, 03:15
00:00

Difficulty:

25% (medium)

Question Stats:

78% (02:08) correct 22% (02:04) wrong based on 283 sessions

### HideShow timer Statistics

A car starts from X and moves towards Y. At the same time another car starts from Y and moves towards X. Both travel at a constant speed and meet after 4 hours. During that time, the faster car traveled 2/3 of the distance XY. How long would it take the slower car to travel the distance XY?

A 6 hours
B. 8 hours
C. 10 hours
D. 12 hours
E. 15 hours

_________________

Srinivasan Vaidyaraman
Sravna Holistic Solutions
http://www.sravnatestprep.com

Holistic and Systematic Approach

Intern
Joined: 01 Oct 2013
Posts: 4
WE: Manufacturing and Production (Manufacturing)
Re: A car starts from X and moves towards Y. At the same time  [#permalink]

### Show Tags

07 Oct 2013, 01:32
Ans is D
This is how
Say Total Dist. XY = 1
Let constant rate of Car X & Car Y be "x" & "y" respectively
Car X distance traveled = 2/3
Time = 4 hrs
Rate of Car X=2/3 div by 4
i.e x = 1/6

When traveling towards each other
Speed = Dist./Time
(x+y) = 1/4
substituting fr "x" in above eqn. we get
y = 1/12
Therefore Time taken to travel Distance XY = 1 div. 1/12
Ans D) 12
Intern
Joined: 12 Sep 2012
Posts: 2
Location: Spain
GPA: 3.95
WE: General Management (Retail)
Re: A car starts from X and moves towards Y. At the same time  [#permalink]

### Show Tags

07 Oct 2013, 03:56
1
My view on this Question:

If one car travelled 2/3, then the other car must have travelled only 1/3, as they are meeting after 4 hours in a certain point. So:

(1/3)XY= 4*y --> It took the car 4 hours to travel 1/3 of the distance at a constant speed y.

So if we solve this last equation:

XY= 3*4*y= 12*y --> It will take this car 12 hours in total to reach its final destination.

Intern
Joined: 21 Sep 2011
Posts: 10
Concentration: General Management
Re: A car starts from X and moves towards Y. At the same time  [#permalink]

### Show Tags

09 Oct 2013, 00:33
SravnaTestPrep wrote:
A car starts from X and moves towards Y. At the same time another car starts from Y and moves towards X. Both travel at a constant speed and meet after 4 hours. During that time, the faster car traveled 2/3 of the distance XY. How long would it take the slower car to travel the distance XY?

A 6 hours
B. 8 hours
C. 10 hours
D. 12 hours
E. 15 hours

D --> Take a smart number (as X travel's 2/3 & Y travel's 1/3 of the distance, i took D = 60 since ,we also have to divide 2/3 & 1/3 by 4 i.e time taken by both car)
D = 60 , therefore , X travels 60*2/3 = 40. Now, since t = 4 , therefore X's speed = 40/4 = 10.
Similarly , Y travels 60*1/3 = 20. Since t=4 , Y's Speed = 20/4 = 5
Therefore total time taken by Y is t = D/S = 60/5 = 12hrs
Intern
Joined: 26 Feb 2012
Posts: 14
GMAT 3: 640 Q49 V29
Re: A car starts from X and moves towards Y. At the same time  [#permalink]

### Show Tags

09 Oct 2013, 07:51
SravnaTestPrep wrote:
A car starts from X and moves towards Y. At the same time another car starts from Y and moves towards X. Both travel at a constant speed and meet after 4 hours. During that time, the faster car traveled 2/3 of the distance XY. How long would it take the slower car to travel the distance XY?

A 6 hours
B. 8 hours
C. 10 hours
D. 12 hours
E. 15 hours

Quick and easy:
It is clear that the slower car is the one starting from Y (car B).
If car B spends 4h to complete d/3 of the traject, then it will spend 8h to complete 2d/3 and 12h to make the whole traject (3d/3).

Intern
Joined: 14 Dec 2011
Posts: 16
Location: India
Concentration: Technology, Nonprofit
GMAT 1: 640 Q48 V29
GMAT 2: 660 Q45 V35
GPA: 3.5
WE: Information Technology (Computer Software)
Re: A car starts from X and moves towards Y. At the same time  [#permalink]

### Show Tags

12 Oct 2013, 01:57
1
2
SravnaTestPrep wrote:
A car starts from X and moves towards Y. At the same time another car starts from Y and moves towards X. Both travel at a constant speed and meet after 4 hours. During that time, the faster car traveled 2/3 of the distance XY. How long would it take the slower car to travel the distance XY?

A 6 hours
B. 8 hours
C. 10 hours
D. 12 hours
E. 15 hours

Take XY = 60 km
Car A travelled distance D1 = 2/3*60 = 40km
Car B travelled distance D2 = 1/3*60 = 20km

Car B is slower, travelling 20 km in 4 hours. Car B speed = 20/4 = 5 km/h

Time for Car B to travel whole distance XY = 60 km:
D = S*T
60 = 5*T
T = 60/5 = 12 hours - Answer.

Hope it helps.
VP
Joined: 02 Jul 2012
Posts: 1176
Location: India
Concentration: Strategy
GMAT 1: 740 Q49 V42
GPA: 3.8
WE: Engineering (Energy and Utilities)
Re: A car starts from X and moves towards Y. At the same time  [#permalink]

### Show Tags

12 Oct 2013, 03:37
2
The faster car travels $$\frac{2}{3}$$ of this distance in 4 hours.

The slower car hence travels $$\frac{1}{3}$$ of this distance in 4 hours.

So, to travel the total distance , the slower car would take 4*3 = 12 hours

_________________

Did you find this post helpful?... Please let me know through the Kudos button.

Thanks To The Almighty - My GMAT Debrief

GMAT Reading Comprehension: 7 Most Common Passage Types

Manager
Joined: 13 Aug 2012
Posts: 95
Re: A car starts from X and moves towards Y. At the same time  [#permalink]

### Show Tags

15 Oct 2013, 00:43
Distance is in the ratio of 2:1 so speed will also be 2:1. Time will be in the ratio of 1:2 because Speed is inversely proportional to time keeping distant constant.
The slowest car's time is $$\frac{1}{3}$$
so $$\frac{1}{3}*x=4$$
$$x=12$$
SVP
Joined: 06 Sep 2013
Posts: 1720
Concentration: Finance
Re: A car starts from X and moves towards Y. At the same time  [#permalink]

### Show Tags

09 Jan 2014, 11:56
SravnaTestPrep wrote:
A car starts from X and moves towards Y. At the same time another car starts from Y and moves towards X. Both travel at a constant speed and meet after 4 hours. During that time, the faster car traveled 2/3 of the distance XY. How long would it take the slower car to travel the distance XY?

A 6 hours
B. 8 hours
C. 10 hours
D. 12 hours
E. 15 hours

4 (x+y) = d

4x = 2/3d

4y = 1/3d

Therefore, y = d/12

D 12 hours
Manager
Joined: 26 Feb 2012
Posts: 100
Location: India
Concentration: General Management, Finance
WE: Engineering (Telecommunications)
Re: A car starts from X and moves towards Y. At the same time  [#permalink]

### Show Tags

16 Feb 2014, 07:34
Lets solve it "plug value" ,method as it about fraction....
Say total distance 3 miles so faster car traveled 2 mile and slower one is 1 mile..

So the slower one traveled 1 mile in 4 hour(because they met in 4 hours) that makes the rate 1/4...
Now lets assume T hour required to cover the distance so 1/4*T=3 So T=12 hours(d) ..ans...

Rgds
Prasannajeet
Director
Joined: 19 Oct 2013
Posts: 509
Location: Kuwait
GPA: 3.2
WE: Engineering (Real Estate)
Re: A car starts from X and moves towards Y. At the same time  [#permalink]

### Show Tags

07 Sep 2018, 17:01
If we let the distance = 12

Then the faster car have travelled 8 miles $$= \frac{2}{3}* 12 = 8$$ miles. As a result the slower car have travelled 4 miles.

Since they meet in 4 hours, then Speed of the slow car $$= \frac{4}{4} = 1$$.

On the basis of our assumption that Distance = 12 then Time would be $$= \frac{12}{1} = 12$$ hours
Re: A car starts from X and moves towards Y. At the same time &nbs [#permalink] 07 Sep 2018, 17:01
Display posts from previous: Sort by