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A car traveled from San Diego to San Francisco at an average speed of

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A car traveled from San Diego to San Francisco at an average speed of [#permalink]

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New post 04 Jul 2016, 08:58
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A car traveled from San Diego to San Francisco at an average speed of 48 miles per hour. If the journey back took twice as long, what was the average speed of the trip?

A. 24.
B. 32.
C. 36.
D. 42.
E. 44.
[Reveal] Spoiler: OA

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Re: A car traveled from San Diego to San Francisco at an average speed of [#permalink]

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New post 04 Jul 2016, 10:19
Let the time taken be = x

One way distance = 48x
Total distance traveled = 2 * 48x = 96x
Total time taken = x + 2x = 3x

Average speed = 96x/3x = 32

Answer: B

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Re: A car traveled from San Diego to San Francisco at an average speed of [#permalink]

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New post 05 Jul 2016, 03:36
another way of doing this !!

let s1 and s2 be the speed
and
let t1 and t2 be the time taken by the car to travel the respective distances

as per the question
t1/t2=1/2

now since speed is inversely proportional to time

s1/s2=2/1
therefore s2 = 24

average speed for the trip = 2s1s2/s1+s2
or,
2*48*24/72= 32 B

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Re: A car traveled from San Diego to San Francisco at an average speed of [#permalink]

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New post 22 Sep 2017, 07:05
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A car traveled from San Diego to San Francisco at an average speed of [#permalink]

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New post 22 Sep 2017, 12:48
-- 48 miles per hour, so let's say the trip took 1 hour (traveled 48 miles there, and 48 miles back)
-- Trip took 2 hours coming back, because it is twice as long
-- Equation: speed = distance/time d = 96, t = 3; 96/3 = 32
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A car traveled from San Diego to San Francisco at an average speed of   [#permalink] 22 Sep 2017, 12:48
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