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A caterer must choose 3 canapés to serve from 12 possible selections.

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SVP
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A caterer must choose 3 canapés to serve from 12 possible selections.  [#permalink]

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New post 12 May 2017, 11:26
2
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

65% (00:50) correct 35% (00:48) wrong based on 83 sessions

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A caterer must choose 3 canapés to serve from 12 possible selections. In how many possible combinations can he serve the 3 canapés?

A. 220
B. 440
C. 660
D. 1,100
E. 1,320

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A caterer must choose 3 canapés to serve from 12 possible selections.  [#permalink]

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New post 12 May 2017, 11:59
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Total ways of serving 3 canapes from a possible 12 combinations can be given by 12c3

12c3 = \(\frac{12*11*10}{3*2}\) = 220(Option A)
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Re: A caterer must choose 3 canapés to serve from 12 possible selections.  [#permalink]

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New post 10 Jan 2018, 10:51
12C3 = 12! / 3! (12!-3!) = 12!/3!*9!

= 12 x 11 x 10 x 9! / 3!*9! ==> Cancel the 9!

12 x 11 x 10 / 6 = 220

Answer = A
GMAT Club Bot
Re: A caterer must choose 3 canapés to serve from 12 possible selections. &nbs [#permalink] 10 Jan 2018, 10:51
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A caterer must choose 3 canapés to serve from 12 possible selections.

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