GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 18 Oct 2019, 12:23

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# A caterer must choose 3 canapés to serve from 12 possible selections.

Author Message
TAGS:

### Hide Tags

Senior RC Moderator
Joined: 02 Nov 2016
Posts: 4118
GPA: 3.39
A caterer must choose 3 canapés to serve from 12 possible selections.  [#permalink]

### Show Tags

12 May 2017, 12:26
2
00:00

Difficulty:

25% (medium)

Question Stats:

66% (00:50) correct 34% (00:48) wrong based on 85 sessions

### HideShow timer Statistics

A caterer must choose 3 canapés to serve from 12 possible selections. In how many possible combinations can he serve the 3 canapés?

A. 220
B. 440
C. 660
D. 1,100
E. 1,320

_________________
Senior PS Moderator
Joined: 26 Feb 2016
Posts: 3333
Location: India
GPA: 3.12
A caterer must choose 3 canapés to serve from 12 possible selections.  [#permalink]

### Show Tags

12 May 2017, 12:59
1
Total ways of serving 3 canapes from a possible 12 combinations can be given by 12c3

12c3 = $$\frac{12*11*10}{3*2}$$ = 220(Option A)
_________________
You've got what it takes, but it will take everything you've got
Intern
Joined: 24 Nov 2016
Posts: 30
Re: A caterer must choose 3 canapés to serve from 12 possible selections.  [#permalink]

### Show Tags

10 Jan 2018, 11:51
12C3 = 12! / 3! (12!-3!) = 12!/3!*9!

= 12 x 11 x 10 x 9! / 3!*9! ==> Cancel the 9!

12 x 11 x 10 / 6 = 220

Re: A caterer must choose 3 canapés to serve from 12 possible selections.   [#permalink] 10 Jan 2018, 11:51
Display posts from previous: Sort by