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01 Aug 2003, 04:35
Kudos
Bookmarks
A ceratin safe has a secret lock consisting to 3 rolling disks; the first being marked 0-9; the second 0-1; the third 0-9 again. John does not know the right code but wants to have the safe open. What is the probability that he will not open it?
(1) 1/200
(2) 1/1000
(3) 999/1000
(4) 199/200
(5) 1/3
(1) 1/200
(2) 1/1000
(3) 999/1000
(4) 199/200
(5) 1/3
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
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01 Aug 2003, 06:40
Kudos
Bookmarks
stolyar
A ceratin safe has a secret lock consisting to 3 rolling disks; the first being marked 0-9; the second 0-1; the third 0-9 again. John does not know the right code but wants to have the safe open. What is the probability that he will not open it?
(1) 1/200
(2) 1/1000
(3) 999/1000
(4) 199/200
(5) 1/3
(1) 1/200
(2) 1/1000
(3) 999/1000
(4) 199/200
(5) 1/3
(4) 199/200 - 10 values for first times 2 for second times 10 for third. = 200. 1 chance out of 200 to open it, means 199/200 to not open it.
Another way to solve this problem would be to just rearrange the order of the dials. Put the 2nd one first, then you're looking at possible values of 0-199 inclusive. Or 200 different numbers.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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