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A certail pool of 12000 liters has two vaults; A to fill the pool and B to pour out. The rate of the filling vault is 500 liters per hour; that of B is 100 lph. The vaults start to work simultaneously. When the pool is half full, the vault A stops to work for 5 hours and 12 minutes and then resumes its working. The vault B works without interruptions. How lond will it take to fill the pool completely?
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A certail pool of 12000 liters has two vaults; A to fill the pool and B to pour out. The rate of the filling vault is 500 liters per hour; that of B is 100 lph. The vaults start to work simultaneously. When the pool is half full, the vault A stops to work for 5 hours and 12 minutes and then resumes its working. The vault B works without interruptions. How lond will it take to fill the pool completely?
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First of all, it doesn't make any difference when A shuts down. so long as there are at least 520 liters in the pool, so you don't have to figure out exactly when the pool is half full. The only thing that is important is that B is draining the pool by itself for 5.2 hours. Hence B dumps 520 liters that the two working together have to make up. So the problem is simply the combined rate of 400 working for some time to fill 12520 liters + 5.2 hours. The answer is 31.3 hours + the 5.2 hours = 36.5 hours.
(1) the pool is half full: 6000=400T; T=15 hours
(2) 5.2 hours, only pouring pipe works, taking away 520 liters, leaving 6000-520=5480 in the pool
(3) together again 12000-5480=400T; T=16.3 hours
(1) the pool is half full: 6000=400T; T=15 hours (2) 5.2 hours, only pouring pipe works, taking away 520 liters, leaving 6000-520=5480 in the pool (3) together again 12000-5480=400T; T=16.3 hours
Finally, 15+5.2+16.3=36.5 hours
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Stolyar, excellent question and excellent answer !
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.