Oct 16 08:00 PM PDT  09:00 PM PDT EMPOWERgmat is giving away the complete Official GMAT Exam Pack collection worth $100 with the 3 Month Pack ($299) Oct 18 08:00 AM PDT  09:00 AM PDT Learn an intuitive, systematic approach that will maximize your success on Fillintheblank GMAT CR Questions. Oct 19 07:00 AM PDT  09:00 AM PDT Does GMAT RC seem like an uphill battle? eGMAT is conducting a free webinar to help you learn reading strategies that can enable you to solve 700+ level RC questions with at least 90% accuracy in less than 10 days. Sat., Oct 19th at 7 am PDT Oct 20 07:00 AM PDT  09:00 AM PDT Get personalized insights on how to achieve your Target Quant Score. Oct 22 08:00 PM PDT  09:00 PM PDT On Demand for $79. For a score of 4951 (from current actual score of 40+) AllInOne Standard & 700+ Level Questions (150 questions)
Author 
Message 
TAGS:

Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 58381

A certain bakery baked a batch of 500 cookies one day. Of those, 320
[#permalink]
Show Tags
06 Apr 2016, 01:17
Question Stats:
42% (02:50) correct 58% (03:06) wrong based on 154 sessions
HideShow timer Statistics
A certain bakery baked a batch of 500 cookies one day. Of those, 320 contained nuts, 230 contained chocolate chips, and 85 contained neither nuts nor chocolate chips. What is the fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch? A. 166 B. 275 C. 413 D. 438 E. 511
Official Answer and Stats are available only to registered users. Register/ Login.
_________________



Verbal Forum Moderator
Status: Greatness begins beyond your comfort zone
Joined: 08 Dec 2013
Posts: 2400
Location: India
Concentration: General Management, Strategy
GPA: 3.2
WE: Information Technology (Consulting)

Re: A certain bakery baked a batch of 500 cookies one day. Of those, 320
[#permalink]
Show Tags
06 Apr 2016, 01:47
Cookies which have both nuts and chocolate chips = 135 Let fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch = x (135+x)/(500+x) = 6/10 =>1350 + 10x = 3000 + 6x => 4x = 1650 => x = 412.5 Therefore x = 413 Answer C
Attachments
OS.PNG [ 3.03 KiB  Viewed 2332 times ]
_________________
When everything seems to be going against you, remember that the airplane takes off against the wind, not with it.  Henry Ford The Moment You Think About Giving Up, Think Of The Reason Why You Held On So Long



Intern
Joined: 15 Jan 2018
Posts: 6

Re: A certain bakery baked a batch of 500 cookies one day. Of those, 320
[#permalink]
Show Tags
25 Mar 2018, 06:34
Bunuel wrote: A certain bakery baked a batch of 500 cookies one day. Of those, 320 contained nuts, 230 contained chocolate chips, and 85 contained neither nuts nor chocolate chips. What is the fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch?
A. 166 B. 275 C. 413 D. 438 E. 511 Thanks in advance for any reply !! Please help me in understanding this question correctly!! Since the question asks for "fewest possible cookies", shouldn't it be that we consider maximum overlap between 320 and 230 i.e. 230 rather 135 and then try to find the "fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch" Considering, 230 as the maximum overlap to find fewest possible .... 3/5 of all the cookies in the batch, as stated above in the solution by Skywalker18. The equation would become as below: (230+x)/(500+x)=6/10 x=175 why is this not correct ? or why is it wrong to consider 230 already having both nuts and choco chips rather than 135?



Manager
Joined: 09 Nov 2015
Posts: 133

Re: A certain bakery baked a batch of 500 cookies one day. Of those, 320
[#permalink]
Show Tags
27 Mar 2018, 00:26
Reply to Itisallinurhead: You are overlooking a basic stipulation of the problem: Of the total 500 cookies, only 85 have neither nuts nor chocolate chips so the number of cookies with nuts or chocolate chips or both are 50085=415 from which we get the 135 overlap. As per your suggestion, we will have 180 (500  320) cookies without chocolate chips or nuts. Hope this clears up the confusion.



Intern
Joined: 15 Jan 2018
Posts: 6

Re: A certain bakery baked a batch of 500 cookies one day. Of those, 320
[#permalink]
Show Tags
28 Mar 2018, 12:43
Itisallinurhead wrote: Bunuel wrote: A certain bakery baked a batch of 500 cookies one day. Of those, 320 contained nuts, 230 contained chocolate chips, and 85 contained neither nuts nor chocolate chips. What is the fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch?
A. 166 B. 275 C. 413 D. 438 E. 511 Thanks in advance for any reply !! Please help me in understanding this question correctly!! Since the question asks for "fewest possible cookies", shouldn't it be that we consider maximum overlap between 320 and 230 i.e. 230 rather 135 and then try to find the "fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch" Considering, 230 as the maximum overlap to find fewest possible .... 3/5 of all the cookies in the batch, as stated above in the solution by Skywalker18. The equation would become as below: (230+x)/(500+x)=6/10 x=175 why is this not correct ? or why is it wrong to consider 230 already having both nuts and choco chips rather than 135? Requesting VeritasPrepKarishma or chetan2u or pushpitkc, please have a look at my comments and provide your inputs Thanks in advance.



Senior PS Moderator
Joined: 26 Feb 2016
Posts: 3341
Location: India
GPA: 3.12

A certain bakery baked a batch of 500 cookies one day. Of those, 320
[#permalink]
Show Tags
28 Mar 2018, 13:13
Itisallinurhead wrote: Itisallinurhead wrote: Bunuel wrote: A certain bakery baked a batch of 500 cookies one day. Of those, 320 contained nuts, 230 contained chocolate chips, and 85 contained neither nuts nor chocolate chips. What is the fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch?
A. 166 B. 275 C. 413 D. 438 E. 511 Thanks in advance for any reply !! Please help me in understanding this question correctly!! Since the question asks for "fewest possible cookies", shouldn't it be that we consider maximum overlap between 320 and 230 i.e. 230 rather 135 and then try to find the "fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch" Considering, 230 as the maximum overlap to find fewest possible .... 3/5 of all the cookies in the batch, as stated above in the solution by Skywalker18. The equation would become as below: (230+x)/(500+x)=6/10 x=175 why is this not correct ? or why is it wrong to consider 230 already having both nuts and choco chips rather than 135? Requesting VeritasPrepKarishma or chetan2u or pushpitkc, please have a look at my comments and provide your inputs Thanks in advance. Hey ItisallinurheadLet's go with your reasoning  If there were 230 cookies which had both nuts and choco chips. There would be 320  230 = 90 cookies which had only nuts and 0 who had only choco chips. We are also told that the number of cookies which contained neither nuts nor chocolate chips is 85. If we to add all of these, we should get the total number of cookies(500). However, we end up short with sum of cookies = 90 + 230 + 85 = 405 Formulae for 2 overlapping set(s) 1. P(Total) = P(A) + P(B)  P(Both) + P(Neither) 2. P(Total) = P(Only A) + P(Only B) + P(Both) + P(Neither)In this problem, we have P(Total) = 500  P(A) = 230  P(B) = 320  P(Neither) = 85 Substituting these values in forumula 1, we get 500 = 230 + 320  P(Both) + 85 Therefore, P(Both) = 635  500 = 135 Hope this helps you!
_________________
You've got what it takes, but it will take everything you've got



Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 9705
Location: Pune, India

Re: A certain bakery baked a batch of 500 cookies one day. Of those, 320
[#permalink]
Show Tags
28 Mar 2018, 21:13
Itisallinurhead wrote: Itisallinurhead wrote: Bunuel wrote: A certain bakery baked a batch of 500 cookies one day. Of those, 320 contained nuts, 230 contained chocolate chips, and 85 contained neither nuts nor chocolate chips. What is the fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch?
A. 166 B. 275 C. 413 D. 438 E. 511 Thanks in advance for any reply !! Please help me in understanding this question correctly!! Since the question asks for "fewest possible cookies", shouldn't it be that we consider maximum overlap between 320 and 230 i.e. 230 rather 135 and then try to find the "fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch" Considering, 230 as the maximum overlap to find fewest possible .... 3/5 of all the cookies in the batch, as stated above in the solution by Skywalker18. The equation would become as below: (230+x)/(500+x)=6/10 x=175 why is this not correct ? or why is it wrong to consider 230 already having both nuts and choco chips rather than 135? Requesting VeritasPrepKarishma or chetan2u or pushpitkc, please have a look at my comments and provide your inputs Thanks in advance. You are given that of 500, only 85 have neither nuts nor chocolate chips. This means 415 MUST have at least one of the two things. If you have an overlap of 230, you are putting the chocolate chips circle inside the 320 nuts circle. Then you have 500  320 = 180 cookies which have neither chocolate chips nor nuts. That is not acceptable. There are only 85 such cookies. Because of this, the overlap is fixed. You do not have a maximum/minimum overlap scenario here. n(C or N) = n(C) + n(N)  Both 415 = 320 + 230  Both Both = 135 (no other value possible) Actually the confusion arises because of the term "fewest possible number of cookies". Why is that required? Why couldn't the question just ask "the number of cookies needed..." It is not because the overlap can vary; it is because you can achieve "more than 3/5" in a variety of ways. 413 makes it just more than 3/5. 414 also makes it more than 3/5. 430 also makes it more than 3/5. 1000 also makes it more than 3/5 and so on...
_________________
Karishma Veritas Prep GMAT Instructor
Learn more about how Veritas Prep can help you achieve a great GMAT score by checking out their GMAT Prep Options >



Intern
Joined: 31 Aug 2019
Posts: 1

Re: A certain bakery baked a batch of 500 cookies one day. Of those, 320
[#permalink]
Show Tags
01 Sep 2019, 03:12
I really love potatoes and this recipe is one of my favorites.
club.cooking/recipe/howtobakepotatoes/ Try baking potatoes for sure.
Ingredients 6 medium sized whole raw potatoes, skin on salt and pepper to taste Extra virgin olive oil




Re: A certain bakery baked a batch of 500 cookies one day. Of those, 320
[#permalink]
01 Sep 2019, 03:12






