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A certain bakery baked a batch of 500 cookies one day. Of those, 320 [#permalink]
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06 Apr 2016, 01:17
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Re: A certain bakery baked a batch of 500 cookies one day. Of those, 320 [#permalink]
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06 Apr 2016, 01:47
Cookies which have both nuts and chocolate chips = 135 Let fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch = x (135+x)/(500+x) = 6/10 =>1350 + 10x = 3000 + 6x => 4x = 1650 => x = 412.5 Therefore x = 413 Answer C
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Re: A certain bakery baked a batch of 500 cookies one day. Of those, 320 [#permalink]
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25 Mar 2018, 06:34
Bunuel wrote: A certain bakery baked a batch of 500 cookies one day. Of those, 320 contained nuts, 230 contained chocolate chips, and 85 contained neither nuts nor chocolate chips. What is the fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch?
A. 166 B. 275 C. 413 D. 438 E. 511 Thanks in advance for any reply !! Please help me in understanding this question correctly!! Since the question asks for "fewest possible cookies", shouldn't it be that we consider maximum overlap between 320 and 230 i.e. 230 rather 135 and then try to find the "fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch" Considering, 230 as the maximum overlap to find fewest possible .... 3/5 of all the cookies in the batch, as stated above in the solution by Skywalker18. The equation would become as below: (230+x)/(500+x)=6/10 x=175 why is this not correct ? or why is it wrong to consider 230 already having both nuts and choco chips rather than 135?



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Re: A certain bakery baked a batch of 500 cookies one day. Of those, 320 [#permalink]
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27 Mar 2018, 00:26
Reply to Itisallinurhead: You are overlooking a basic stipulation of the problem: Of the total 500 cookies, only 85 have neither nuts nor chocolate chips so the number of cookies with nuts or chocolate chips or both are 50085=415 from which we get the 135 overlap. As per your suggestion, we will have 180 (500  320) cookies without chocolate chips or nuts. Hope this clears up the confusion.



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Re: A certain bakery baked a batch of 500 cookies one day. Of those, 320 [#permalink]
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28 Mar 2018, 12:43
Itisallinurhead wrote: Bunuel wrote: A certain bakery baked a batch of 500 cookies one day. Of those, 320 contained nuts, 230 contained chocolate chips, and 85 contained neither nuts nor chocolate chips. What is the fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch?
A. 166 B. 275 C. 413 D. 438 E. 511 Thanks in advance for any reply !! Please help me in understanding this question correctly!! Since the question asks for "fewest possible cookies", shouldn't it be that we consider maximum overlap between 320 and 230 i.e. 230 rather 135 and then try to find the "fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch" Considering, 230 as the maximum overlap to find fewest possible .... 3/5 of all the cookies in the batch, as stated above in the solution by Skywalker18. The equation would become as below: (230+x)/(500+x)=6/10 x=175 why is this not correct ? or why is it wrong to consider 230 already having both nuts and choco chips rather than 135? Requesting VeritasPrepKarishma or chetan2u or pushpitkc, please have a look at my comments and provide your inputs Thanks in advance.



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A certain bakery baked a batch of 500 cookies one day. Of those, 320 [#permalink]
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28 Mar 2018, 13:13
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Itisallinurhead wrote: Itisallinurhead wrote: Bunuel wrote: A certain bakery baked a batch of 500 cookies one day. Of those, 320 contained nuts, 230 contained chocolate chips, and 85 contained neither nuts nor chocolate chips. What is the fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch?
A. 166 B. 275 C. 413 D. 438 E. 511 Thanks in advance for any reply !! Please help me in understanding this question correctly!! Since the question asks for "fewest possible cookies", shouldn't it be that we consider maximum overlap between 320 and 230 i.e. 230 rather 135 and then try to find the "fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch" Considering, 230 as the maximum overlap to find fewest possible .... 3/5 of all the cookies in the batch, as stated above in the solution by Skywalker18. The equation would become as below: (230+x)/(500+x)=6/10 x=175 why is this not correct ? or why is it wrong to consider 230 already having both nuts and choco chips rather than 135? Requesting VeritasPrepKarishma or chetan2u or pushpitkc, please have a look at my comments and provide your inputs Thanks in advance. Hey ItisallinurheadLet's go with your reasoning  If there were 230 cookies which had both nuts and choco chips. There would be 320  230 = 90 cookies which had only nuts and 0 who had only choco chips. We are also told that the number of cookies which contained neither nuts nor chocolate chips is 85. If we to add all of these, we should get the total number of cookies(500). However, we end up short with sum of cookies = 90 + 230 + 85 = 405 Formulae for 2 overlapping set(s) 1. P(Total) = P(A) + P(B)  P(Both) + P(Neither) 2. P(Total) = P(Only A) + P(Only B) + P(Both) + P(Neither)In this problem, we have P(Total) = 500  P(A) = 230  P(B) = 320  P(Neither) = 85 Substituting these values in forumula 1, we get 500 = 230 + 320  P(Both) + 85 Therefore, P(Both) = 635  500 = 135 Hope this helps you!
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Re: A certain bakery baked a batch of 500 cookies one day. Of those, 320 [#permalink]
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28 Mar 2018, 21:13
Itisallinurhead wrote: Itisallinurhead wrote: Bunuel wrote: A certain bakery baked a batch of 500 cookies one day. Of those, 320 contained nuts, 230 contained chocolate chips, and 85 contained neither nuts nor chocolate chips. What is the fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch?
A. 166 B. 275 C. 413 D. 438 E. 511 Thanks in advance for any reply !! Please help me in understanding this question correctly!! Since the question asks for "fewest possible cookies", shouldn't it be that we consider maximum overlap between 320 and 230 i.e. 230 rather 135 and then try to find the "fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch" Considering, 230 as the maximum overlap to find fewest possible .... 3/5 of all the cookies in the batch, as stated above in the solution by Skywalker18. The equation would become as below: (230+x)/(500+x)=6/10 x=175 why is this not correct ? or why is it wrong to consider 230 already having both nuts and choco chips rather than 135? Requesting VeritasPrepKarishma or chetan2u or pushpitkc, please have a look at my comments and provide your inputs Thanks in advance. You are given that of 500, only 85 have neither nuts nor chocolate chips. This means 415 MUST have at least one of the two things. If you have an overlap of 230, you are putting the chocolate chips circle inside the 320 nuts circle. Then you have 500  320 = 180 cookies which have neither chocolate chips nor nuts. That is not acceptable. There are only 85 such cookies. Because of this, the overlap is fixed. You do not have a maximum/minimum overlap scenario here. n(C or N) = n(C) + n(N)  Both 415 = 320 + 230  Both Both = 135 (no other value possible) Actually the confusion arises because of the term "fewest possible number of cookies". Why is that required? Why couldn't the question just ask "the number of cookies needed..." It is not because the overlap can vary; it is because you can achieve "more than 3/5" in a variety of ways. 413 makes it just more than 3/5. 414 also makes it more than 3/5. 430 also makes it more than 3/5. 1000 also makes it more than 3/5 and so on...
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Re: A certain bakery baked a batch of 500 cookies one day. Of those, 320
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