MacFauz
A certain business school has 500 students, and the law school at the same university has 800 students. Among these students, there are 30 sibling pairs consisting of 1 business student and 1 law student. If 1 student is selected at random from both schools, what is the probability that a sibling pair is selected?
A. \(\frac{3}{40000}\)
B. \(\frac{3}{20000}\)
C. \(\frac{3}{4000}\)
D. \(\frac{9}{400}\)
E. \(\frac{6}{130}\)
P(selecting a sibling pair) = P(select a business student with a sibling
AND select a law student who is that business student's sibling)
= P(select a business student with a sibling)
x P(select a law student who is that business student's sibling)
= 30/500
x 1/800
= 30/400,000
= 3/40,000
Answer: A
Note: P(select a business student with a sibling) = 30/500, because 30 of the 500 business students have a sibling in law school.
P(select a law student who is that business student's sibling) = 1/800, because there are 800 law students and only 1 is the sibling of the selected business student.
Cheers,
Brent
Why arent we multiplying with 2 in this case ? Why can we not pick law school sibling first and then business ? wouldnt that make the answer to be B ?