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# A certain company employs 6 senior officers and 4 junior

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Intern
Joined: 25 Aug 2008
Posts: 30

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A certain company employs 6 senior officers and 4 junior [#permalink]

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14 Oct 2008, 17:17
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A certain company employs 6 senior officers and 4 junior officers. If a committee is to be created that is made up of 3 senior officers and 1 junior officer, how many different companies are possible?

a. 8
b. 24
c. 58
d. 80
e. 210

Thanks.

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Senior Manager
Joined: 21 Apr 2008
Posts: 269

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Location: Motortown

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14 Oct 2008, 17:31
D
6C3 * 4C1 = 20 * 4 = 80

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Intern
Joined: 25 Aug 2008
Posts: 30

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14 Oct 2008, 17:34
I apologize for my ignorance but I'm new to the forum and don't know what 'C' stands for. Please elaborate!

:D

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Intern
Joined: 23 Sep 2008
Posts: 15

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14 Oct 2008, 23:24
The answer is 6C3*4C1 = 80.

C means combinations wherein nCr = n!/(r!)(n-r)!

n! = 1X2X..........(n-1)Xn

Hope that helps. And the question is a combinatorics problem and a combination part and not a permutation problem.

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Re: Permutation Problem?   [#permalink] 14 Oct 2008, 23:24
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