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Both your answers are very helpful, indeed! Thanks a lot! I somehow managed to confuse myself with the "half the time" aspect of the exercise. I started thinking in terms of 24 hours etc etc yet it was that simple (signing it with a "t"). A simple reminder that I should keep things simple and to the point! The only logical thinking that I did was to eliminate answers A, D and E since the time needed to do the run, has to be longer than 2.4 hours and less than 4.
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DrFeelgood
Both your answers are very helpful, indeed! Thanks a lot! I somehow managed to confuse myself with the "half the time" aspect of the exercise. I started thinking in terms of 24 hours etc etc yet it was that simple (signing it with a "t"). A simple reminder that I should keep things simple and to the point! The only logical thinking that I did was to eliminate answers A, D and E since the time needed to do the run, has to be longer than 2.4 hours and less than 4.

Thats the great way to eliminate 3 options.
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1. A day's run of milk is processed by p and q together and also by q alone.
2. Let the total time taken be x.
3. x = time taken by p and q together/ 2 + time taken by q alone /2
4. i.e., 1/x = (1/4 + 1/6)/2 + (1/4)/2
5. x= 3
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x = total time

1/x = 1/2*1/4 (Q alone) + 1/2*1/2.4 (P & Q simultaneously) = 1/8 + 1/2*24/10 = 1/8 + 5/24 = 8/24

--> x = 24/8 = 3 --> B.
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Rate (P) = 1/2
Rate (Q) = 3/4

P+Q (2.4)= work done = 3

Let 't' be the total time for the scenario then

(3/4) t/2 + t/2 (3/4 + 1/2) = 3

t=3
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Hi All,

This question can be solved by TESTing THE ANSWERS.

We're given rates for Machine P (30 gallons/minute) and Machine Q (45 gallons/minute) and we're told how long it would take each machine to finish a job (6 hours and 4 hours respectively). We can use this information to figure out the TOTAL JOB....

Total Job = (30 gallons/min)(60 mins)(6 hours) = 10,800 Gallons

We're then given a specific set of circumstances to calculate: Machine Q works by itself for a period of time, then the two machine work together for the SAME amount of time that Machine Q worked by itself. We're told that this situation will complete the entire job. We're asked how long it would take to complete the job under these circumstances.

Logically, since Machine Q can do the entire job on its own in 4 hours, with the added help of Machine P, the amount of time MUST be LESS than 4 hours.

Let's TEST Answer B....

If the Total job was 3 hours, then Machine Q would work for 1.5 hours by itself, then Machines P and Q would work for another 1.5 hours together. We can now calculate how many Gallons are processed in this situation...

Machine Q = (45 gallons/min)(90 minutes) = 4,050 gallons
Machines P+Q = (45+30 gallons/min)(90 minutes) = 6,750 gallons
Total = 4,050 + 6,750 = 10,800 gallons.
This IS the exact TOTAL we are supposed to end up with, so the total time MUST be 3 hours.

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A certain dairy packing plant has two machines, P and Q, that process milk at constant rates of 30 gallons per minute and 45 gallons per minute, respectively. A day's run of milk can be processed by machine P operating alone in 6 hours, by machine Q operating alone in 4 hours, or by both machines operating simultaneously in 2.4 hours. If a day's run of milk is processed using machine Q alone for half the time and both machines together for half the time, how many hours does it take to complete the run?

    A. 1.5
    B. 3.0
    C. 3.75
    D. 4.2
    E. 5.0

let w=portion of work done by Q alone
1-w=portion of work done by P and Q
w/(1/4)=(1-w)/(1/4+1/6)
w=3/8 of run completed by Q alone
(3/8)/(1/4)=3/2 hours for Q alone
(3/2)*2=3 hours total to complete run
B
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DrFeelgood
A certain dairy packing plant has two machines, P and Q, that process milk at constant rates of 30 gallons per minute and 45 gallons per minute, respectively. A day's run of milk can be processed by machine P operating alone in 6 hours, by machine Q operating alone in 4 hours, or by both machines operating simultaneously in 2.4 hours. If a day's run of milk is processed using machine Q alone for half the time and both machines together for half the time, how many hours does it take to complete the run?

    A. 1.5
    B. 3.0
    C. 3.75
    D. 4.2
    E. 5.0

I stumbled upon this one yesterday and it kind of confused me, though I have pretty much understood the logic behind work problems. Ideas? Thanks in advance!

Done in 30 seconds: Q alone does the work in 4 hours, 2 machines together in 2,4 hours. Therefore, eliminate A, D and E. Taking into account that Q operated for half the time and both machines together for half the time - the answer should be somewhere close to the average of these times. C is very close to the time that needed for Q if operating alone. B is the answer.
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I had one doubt: Q operating alone in 4 hours will be 45*4*60 which is not equal to P alone = 30*6*60 but both should be ideally equal as day's run of milk is constant
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shisingh
I had one doubt: Q operating alone in 4 hours will be 45*4*60 which is not equal to P alone = 30*6*60 but both should be ideally equal as day's run of milk is constant
45 * 4 * 60 = 30 * 6 * 60 = 10800
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Hey!

45 x 4 x 60 = 180 x 60
30 x 6 x 60 = 180 x 60.


shisingh
I had one doubt: Q operating alone in 4 hours will be 45*4*60 which is not equal to P alone = 30*6*60 but both should be ideally equal as day's run of milk is constant
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Usually we shouldn't add individual rates in Work-Rate Problems right? Why is that not the case here? Why are we adding 30+45 for total work done.
Zarrolou
\(rate*time=work\)
\(45=\)rate Q/min
\(30=\)rate P/min
\(30+45=\)rate Q+P/min

Let \(t\) be half of the time necessary, expressed in minutes. The total work of a day is \(6 h*60 min*30r/min\).

\(45*t + t(30+45)=6*60*30\) or \(120t=6*60*30\), \(t=90\) minutes. \(t\) is half of the time , so the total is \(180\) minutes or \(3\) hours.

Hope it's clear
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Usually we shouldn't add individual rates in Work-Rate Problems right? Why is that not the case here? Why are we adding 30+45 for total work done.
ZarrolA certain dairy packing plant has two machines, P and Q, that process milk at constant rates of 30 gallons per minute and 45 gallons per minute, respectively. A day's run of milk can be processed by machine P operating alone in 6 hours, by machine Q operating alone in 4 hours, or by both machines operating simultaneously in 2.4 hours. If a day's run of milk is processed using machine Q alone for half the time and both machines together for half the time, how many hours does it take to complete the run?A. 1.5B. 3.0C. 3.75D. 4.2E. 5.0ou


\(rate*time=work\)
\(45=\)rate Q/min
\(30=\)rate P/min
\(30+45=\)rate Q+P/min

Let \(t\) be half of the time necessary, expressed in minutes. The total work of a day is \(6 h*60 min*30r/min\).

\(45*t + t(30+45)=6*60*30\) or \(120t=6*60*30\), \(t=90\) minutes. \(t\) is half of the time , so the total is \(180\) minutes or \(3\) hours.

Hope it's clear

We add the rates because both machines are working on the same milk run at the same time. Their combined rate is 30 + 45 = 75 gallons per minute, which means together they process 75 gallons every minute.
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