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05 Dec 2024, 01:30
Kudos
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
54% (02:34) correct
46%
(02:29)
wrong
based on 156
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A certain shop in a market sells only cherry pies and apple pies, where an apple pie costs 20% more than cherry pies. If the shop’s pie sales on Wednesday totaled $111, how many cherry pies were sold?
(1) Cherry pies cost $15 each.
(2) The shop sold a total of 7 pies on Wednesday.
(1) Cherry pies cost $15 each.
(2) The shop sold a total of 7 pies on Wednesday.
06 Dec 2024, 15:17
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Bunuel
\(x= #\) of Apples and \(a\) cost of each apple.
\(y= #\) of Cherry pies and \(c\) cost of each cherry pie.
\(a*x + c *y = 111\)
\(a = 1.2c\)... (i)
\(1.2c*x +c*y =111\)...(ii)
(1) Cherry pies cost $15 each.
\(c=15\)
Therefore \( a =18\) ... from (i)
\(18x+ 15y =111\) ... from (ii)
Note \(x\) and \(y\) are integers.
After trial and error we find that \(x= 2\) and \(y= 5\) are the only values that satisfy the last equation.
SUFF.
(2) The shop sold a total of 7 pies on Wednesday.
\(1.2c*x +c*y =111\)
\(x+y =7 \)
We have three variables and two equations, these equations cannot be solved for \(x\) and \(y.\)
INSUFF.
Ans A
Hope it helped.
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