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08 May 2015, 16:38
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A certain singer at an outdoor concert can be heard for 1 mile in all directions. after an adjustment is made to her microphone, the singer can be heard for 2 miles in all directions. by approximately how many square miles was the region in which should could be hard increased by the adjustment?
A. 1 square mile
B. π sq. miles
c. 2π sq. miles
D.3π sq. miles
E. 4π sq. miles
A. 1 square mile
B. π sq. miles
c. 2π sq. miles
D.3π sq. miles
E. 4π sq. miles
08 May 2015, 16:51
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If anyone within 1 mile of the singer can hear her, that means there is a circle centered at the singer of radius 1 mile, and anyone within that circle can hear the singer. The area of that circle is π r^2 = π (1)^2 = π
After the microphone is adjusted, there is a circle of radius 2 miles around the singer, and anyone within that circle can hear her. The area of this new circle is π r^2 = π (2)^2 = 4π
The increase in area is just found by subtracting: 4π - π = 3π
After the microphone is adjusted, there is a circle of radius 2 miles around the singer, and anyone within that circle can hear her. The area of this new circle is π r^2 = π (2)^2 = 4π
The increase in area is just found by subtracting: 4π - π = 3π
09 Dec 2022, 07:40
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