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A certain train is traveling at a constant rate. If the train travels

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A certain train is traveling at a constant rate. If the train travels  [#permalink]

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New post 26 Jun 2018, 21:11
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Question Stats:

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A certain train is traveling at a constant rate. If the train travels s miles in t hours, in how many hours will the train travel y miles?


A. \(\frac{sy}{t}\)

B. \(\frac{st}{y}\)

C. \(\frac{ty}{s}\)

D. \(\frac{s}{ty}\)

E. \(\frac{s+y}{t}\)

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Re: A certain train is traveling at a constant rate. If the train travels  [#permalink]

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New post 26 Jun 2018, 22:36
Bunuel wrote:
A certain train is traveling at a constant rate. If the train travels s miles in t hours, in how many hours will the train travel y miles?


A. \(\frac{sy}{t}\)

B. \(\frac{st}{y}\)

C. \(\frac{ty}{s}\)

D. \(\frac{s}{ty}\)

E. \(\frac{s+y}{t}\)


As the calculation we're asked to do is relatively straightforward, we'll just do it.
This is a Precise approach.

We're told that the train traveled s miles in t hours, that is it traveled s/t miles per hour.
Since distance = time * speed, then y = time * s/t and our answer is yt/s

(C) is our answer
T
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Re: A certain train is traveling at a constant rate. If the train travels  [#permalink]

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New post 26 Jun 2018, 22:37

Solution



Given:
    • A certain train is traveling at a constant rate
    • The train travels s miles in t hours
      o Hence, speed of the train = \(\frac{s}{t}\) miles per hour

To find:
    • The time the train will take to travel y miles

Approach and Working:
As the speed of the train is \(\frac{s}{t}\) mph,
    • The time the train will take to travel y miles = y/(s/t) hours = \(\frac{ty}{s}\) hours

Hence, the correct answer is option C.

Answer: C
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A certain train is traveling at a constant rate. If the train travels  [#permalink]

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New post 26 Jun 2018, 22:57
No need of speed formula here

s miles -> t hours
y miles -> ? hours

Cross multiply: s * ? = yt
? = yt / s

Answer: C
A certain train is traveling at a constant rate. If the train travels &nbs [#permalink] 26 Jun 2018, 22:57
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