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RSOHAL
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Hi Pepo,

Yes, your idea is correct - I'm just going to 'edit' your language a bit...

You're STARTING with 5kg of cement. Since the ratio is 1:3:5, that means you're multiplying the "1" by "5" to get 5kg... so you have to multiply the other two numbers in the ratio by 5 (the "3" and the "5"). Doing so gives you...

5 kg cement + 15 kg sand + 25 kg gravel = 45 kg concrete

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Correct option : E

Given Information : Ration of (Cement : Sand : Garvel) = (1 : 3 : 5)
To Find : mixture breakup of 5 kg brick
Total Mixture : (1x +3x +5x) = 9x

C+S+G
= \(\frac{1}{9}\) *5 + \(\frac{3}{9}\) *5 + \(\frac{5}{9}\) *5
= 5

(1*5 + 3*5 + 5*5) = 45 (Option E)
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RSOHAL
A certain type of concrete mixture is to be made of cement, sand and gravel in a ratio 1:3:5 by weight. What is the greatest number of kilograms of this mixture that can be made with 5 kilograms of cement ?

(A) \(13\frac{1}{2}\)

(B) \(15\)

(C) \(25\)

(D) \(40\)

(E) \(45\)


Source: OG 1988 Q1 PS Test Section-1

\(C : S : G = x:3x:5x\)

\(x\) represents \(5\), So \(x + 3x + 5x = 9x \) will be \(9*5 = 45\), Answer must be \((E) 45\)
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