|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
23 Nov 2022, 09:45
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
45% (02:02) correct
55%
(01:20)
wrong
based on 55
sessions
History
Date
Time
Result
Not Attempted Yet
A circle in the xy-plane is given by the equation \((x−a)^2+(y−b)^2=c^2\), where a, b, and c are nonzero constants. If the point \((b+a, b−a)\) lies on the circle, which of the following is an equation of the tangent line to the circle at this point?
A. \(y=ab(x−a−b)+(a−b)\)
B. \(y=ab(x−a+b)+(a+b)\)
C. \(y=ab(x−b+a)+(a+b)\)
D. \(y=ba(x−b+a)+(a+b)\)
E. \(y=ba(x−b−a)+(b−a)\)
A. \(y=ab(x−a−b)+(a−b)\)
B. \(y=ab(x−a+b)+(a+b)\)
C. \(y=ab(x−b+a)+(a+b)\)
D. \(y=ba(x−b+a)+(a+b)\)
E. \(y=ba(x−b−a)+(b−a)\)
11 Jan 2023, 01:27
Kudos
Bookmarks
Bunuel
The circle has its center, O, at (a,b) and the radius of the circle is C.
Let the point of tangency be T.
Coordinate of T = (b+a, b−a)
Slope of OT = \(\frac{y_2 - y_1 }{ x_2 - x_1}\)
\(\frac{b-a-b }{ b+a-a} = \frac{-a}{b}\)
Slope of a line perpendicular to OT = \(\frac{b}{a}\)
Slope of the line at point \((b+a, b−a)\) with slope \(\frac{b}{a}\)
\(y - y_1 = m (x - x_1)\)
\(y - (b - a) = \frac{b}{a} (x - (a + b))\)
\(y - (b - a) = \frac{b}{a} (x- b - a)\)
\(y = \frac{b}{a} (x - b - a) + (b - a)\)
General Discussion
24 Sep 2024, 22:50
Kudos
Bookmarks
Automated notice from GMAT Club BumpBot:
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
