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A circular wheel travels along a flat surface at a constant

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VP
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Joined: 30 Jun 2008
Posts: 1008
A circular wheel travels along a flat surface at a constant [#permalink]

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New post 25 Oct 2008, 10:10
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A circular wheel travels along a flat surface at a constant rate of 2.5 feet per second. How many complete revolutions will the wheel make in 50 seconds if its diameter is 3 feet ?

* 6
* 10
* 13
* 14
* 19

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Re: PS : WHEEL [#permalink]

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New post 25 Oct 2008, 10:29
amitdgr wrote:
A circular wheel travels along a flat surface at a constant rate of 2.5 feet per second. How many complete revolutions will the wheel make in 50 seconds if its diameter is 3 feet ?

* 6
* 10
* 13
* 14
* 19


13

2.5 fps

circumference = 2 X pi X r = 3.14 X 3 = 9.42 ft

1 sec - 2.5 ft

50 sec - 125 ft

9.42 ft approx 9.5 ft is 1 rev

125 ft - how many revolutions

125/9.5 = 13.4

Completed 13 revolutions and in the 14th revolution.
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Re: PS : WHEEL [#permalink]

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New post 25 Oct 2008, 13:00
C - 13

Feet in 50 seconds - 2.5*50 = 125
Circumference = 3*pi

Revolutions = 125/(3*pi) ~ 13

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Re: PS : WHEEL   [#permalink] 25 Oct 2008, 13:00
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A circular wheel travels along a flat surface at a constant

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