|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
12 Mar 2021, 03:16
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
56% (03:10) correct
44%
(02:23)
wrong
based on 99
sessions
History
Date
Time
Result
Not Attempted Yet
A committee of 8 persons has to be formed from 15 persons A, B, C, D, ..., O. In how many ways this can be done if:
(i) A, E, I are always together;
(ii) B, H and K will not be there if E is in the committee;
(iii) F and G are always selected.
(A) 35
(B) 45
(C) 119
(D) 210
(E) 245
(i) A, E, I are always together;
(ii) B, H and K will not be there if E is in the committee;
(iii) F and G are always selected.
(A) 35
(B) 45
(C) 119
(D) 210
(E) 245
29 Mar 2021, 11:08
Kudos
Bookmarks
Bunuel
Solution:
If A, E, I, F, and G are on the committee, then B, H, and K are not (since E is on the committee). Therefore, we only have 3 more people to choose from 7 available people for the committee, and this can be done in 7C3 = (7 x 6 x 5) / (3 x 2) = 35 ways.
If F and G are on the committee, but A, E and I are not, then we have 6 more people to choose from 10 available people for the committee. This can be done in 10C6 = 10C4 = (10 x 9 x 8 x 7) / (4 x 3 x 2) = 10 x 3 x 7 = 210 ways.
Therefore, there are a total of 35 + 210 = 245 ways to form the committee.
Answer: E
22 May 2022, 00:54
Kudos
Bookmarks
Automated notice from GMAT Club BumpBot:
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
