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kevincan
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A for me.

(1) The company's total revenue from bicycle sales in 2006 was between $11 million and $13 million and 10% higher than it was in 2005.
SUFFICIENT

Let T=total revenue, M=revenue from mountain bikes, and R=revenue from racing bikes for Year 2005.

Then for 2006, the figures will be,
1.1T, 1.05M, and 1.20R.

Set up the equations.
M+R=T
1.05M+1.2R=1.1T
1.1T=11~13

Three unknowns, three equations -> solvable.

Let's test the range for the total revenue in 2006.
Let 1.1T=11.
Then, T=10.
Solve M+R=10
1.05M+1.20R=11
R=3.3333 < 4

Let 1.1T=13
Then, T=11.8 approx.
Solve M+R=11.8
1.05M+1.20R=13
R=2.6666 < 4

Therefore, the revenue from racing bike sales did NOT exceed 4 million in 2006.

(2) More than 40% of the bicycles that the company sold in 2006 were racing bikes.
INSUFFICIENT
We don't know how much racing bikes sell for, let alone the total revenue in 2006.

Therefore, A.
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St1:
Taking the worst case revenue of $11m, we know in in 2005, the revenue was $9.9m

So if revenues of racing bikes = r, then revenues of mountain bikes = 9.9-r

In 2006, revenues of racing bikes = 1.2r and revenues of mountina bikes = 1.05(9.9-r)

So total revenue in 2006 = 1.2r + 1.05(9.9-r) = 11

We can solve for r. Sufficient.

St2:
We are still in the murky region here since all we know is the percentage of racing bikes:mountain bikes sold (in fact, even this figure is murky because we are told more than 40% are racing bikes). Nothing else is revealed. Insufficient.

Ans A



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