Bunuel
A contract is to be completed in 46 days and 117 men were set to work, each working 8 hours a day. After 33 days, (4/7) of the work is completed. How many additional men may be employed so that the work may be completed in time, each man now working 9 hours?
(A) 80
(B) 81
(C) 82
(D) 83
(E) 84
After 33 days, \(\frac{4}{7}\)th of the work is completed.
117*8*33 man-hours of work are completed at the end of 33 days if we assume
each worker does 1 unit of work in an hour. Since this is \(\frac{4}{7}\)th of the total work
needed to be done(let the total work in man-hours be x)
\(\frac{4x}{7} = 117*8*33\) -> \(x = \frac{117*7*33*8}{4} = 117*7*33*2\) man-hours.
Pending work is \(117*7*33*2 - 117*8*33 = 117*33*(14-8)= 117*33*6\) man-hours
For the remaining 13 days, let m be the number of men who do the work
\(m*9*13 = 117*33*6\) -> \(m = \frac{117*33*6}{9*13} = 198\). Extra men needed for the job \(= 198 -117 = 81\)
Therefore, since 117 men were already working,
81(Option B) more men are required to finish the work.