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A cookery course is divided into two groups. In group X, the average

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Math Expert
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Joined: 02 Sep 2009
Posts: 58340
A cookery course is divided into two groups. In group X, the average  [#permalink]

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New post 25 Sep 2018, 04:49
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

77% (01:42) correct 23% (02:07) wrong based on 34 sessions

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Joined: 19 Oct 2013
Posts: 519
Location: Kuwait
GPA: 3.2
WE: Engineering (Real Estate)
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Re: A cookery course is divided into two groups. In group X, the average  [#permalink]

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New post 28 Sep 2018, 15:38
Let a be the number of trainees in group X

76*a + 70 (30 - a) = 30*74

76a + 2,100 - 70a = 2,220

6a = 120
a = 20

Answer choice C

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Re: A cookery course is divided into two groups. In group X, the average  [#permalink]

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New post 29 Sep 2018, 05:47

Solution



Given:
    • A cookery course is divided into two groups – X and Y.
    • Total trainees in two groups combined: 30.
    • In group X, the average score is 76.
    • In group Y, the average score is 70.
    • Overall average score of two groups combined: 74.

To find:
    • Number of trainees in group X.

Approach and Working:
If group X has n trainees, then group Y has (30 – n) trainees.
    • Total score of group X = n x 76 = 76n
    • Total score of group Y = (30 – n) x 70 = 2100 – 70n
    • Total score of both groups combined = 30 x 74 = 2220

Therefore, we can write,
    • 76n + 2100 – 70n = 2220
    Or, 6n = 120
    Or, n = 20

Hence, the correct answer is option C.

Answer: C

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Re: A cookery course is divided into two groups. In group X, the average   [#permalink] 29 Sep 2018, 05:47
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