Bunuel
apoorvasrivastva
A cube marked 1, 2, 3, 4, 5, and 6 on its six faces. Three colors, red, blue, and green are used to paint the six faces of the cube. If the adjacent faces are painted with the different colors, in how many ways can the cube be painted?
(A) 3
(B) 6
(C) 8
(D) 12
(E) 27
If the base of the cube is red, then in order the adjacent faces to be painted with the different colors, the top must also be red. 4 side faces can be painted in Green-Blue-Green-Blue OR Blue-Green-Blue-Green (2 options).
But we can have the base painted in either of the three colors, thus the total number of ways to paint the cube is 3*2=6.
Answer: B.
Dear
BunuelWith the top and base of the cube being red, whether 4 side faces are
Green-Blue-Green-Blue OR Blue-Green-Blue-Green (2 options) it should not matter because using the top and base as the axis, we can rotate
Green-Blue-Green-Blue[i] to be [i]Blue-Green-Blue-Green right?
So according to the solution, why there are 2 distinct options?
Those 2 options should be counted as 1 because it can be rotated.
Please shed some light
Thank you!