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Ev123
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Ev123

2- On level farmland, two runners leave at the same time from the intersection of two country roads. One runner jogs due north at a constant rate of 8 miles per hour while the second runner jogs due east at a constant rate that is 4 miles per hour faster than the first runner’s rate. How far apart, to the nearest mile, will they be after 21hour?
(A) 6
(B) 7
(C) 8
(D) 12
(E) 14



Solution:
Setup a triangle with legs as the distance run by the runners. The hypotenuse is what we will solve for.

Runner A
8 miles / hour = 21 hours = 168 miles
Runner B
12 miles / hour = 252 miles

So triangle with a = 168 and b = 252
pythagoream theorem - However I at 21 hours I don't get 7.

Is there an an error in the question?
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GMATBLACKBELT
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Ev123
Please provide detailed answers :)
OA are in Bold Face :)

Thanks!

1- Working alone, a small pump takes twice as long as a large pump takes to fill an empty tank. Working together at their respective constant rates, the pumps can fill the tank in 6 hours. How many hours would it take the small pump to fill the tank working alone?
(A) 8
(B) 9
(C) 12
(D) 15
(E) 18

2- On level farmland, two runners leave at the same time from the intersection of two country roads. One runner jogs due north at a constant rate of 8 miles per hour while the second runner jogs due east at a constant rate that is 4 miles per hour faster than the first runner’s rate. How far apart, to the nearest mile, will they be after 21hour?
(A) 6
(B) 7
(C) 8
(D) 12
(E) 14

3- If x = y + 4 and x = 20 – y, then (x^2) - (y^2)=
(A) 16
(B) 80
(C) 144
(D) 256
(E) 384


1: R is 1/x for small pipe so 2/x is rate for big pipe.

1/x+2/x=1/6 --> x=18
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Ev123

2- On level farmland, two runners leave at the same time from the intersection of two country roads. One runner jogs due north at a constant rate of 8 miles per hour while the second runner jogs due east at a constant rate that is 4 miles per hour faster than the first runner’s rate. How far apart, to the nearest mile, will they be after 21hour?
(A) 6
(B) 7
(C) 8
(D) 12
(E) 14


Solution:
Setup a triangle with legs as the distance run by the runners. The hypotenuse is what we will solve for.

Runner A
8 miles / hour = 21 hours = 168 miles
Runner B
12 miles / hour = 252 miles

So triangle with a = 168 and b = 252
pythagoream theorem - However I at 21 hours I don't get 7.

Is there an an error in the question?



Yes I am so sorry it is actually (1/2)hour. Copy Paste didn't work out so well!
Thank you for the detailed answer!!
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yuefei
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Blackbelt method for Q2 is much easier. Where s and t are amount completed in 1 hour.

1/s + 1/t = 1/t
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168^2 + 252^2 = c^2 = 7

This does not equal 7.



I call shannagons on these problems except for 1. If you meant a half hour for question 2 I can see this b/c sqrt 52 ~ 7.


The third one is def. a typo. The answer is 80.
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GMATBLACKBELT
168^2 + 252^2 = c^2 = 7

This does not equal 7.



I call shannagons on these problems except for 1. If you meant a half hour for question 2 I can see this b/c sqrt 52 ~ 7.


The third one is def. a typo. The answer is 80.

For 2 - I get rates of 12 and 8 - so 4 and 6 respectively - so the distance between the runners will be sqrt of 4^2 + 6^2 = sqrt 36 + 16 = sqrt 52 - closest option is 7.
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I agree. Isn't there something in the forum rules about shenanigan's :)
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Ev123
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I agree on Question 3!

I kept getting 80. Really confused about the official answer.

I should call GMAT and ask for an automatic 800 for finding a mistake on their study materials ;)

Do you think it will work?! lol.

Thanks for the help guys I really appreciate it!

~ Ev



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