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# A frame 2 inches wide is placed around a rectangular picture with dime

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Math Expert
Joined: 02 Sep 2009
Posts: 55803
A frame 2 inches wide is placed around a rectangular picture with dime  [#permalink]

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11 Jan 2019, 01:51
00:00

Difficulty:

35% (medium)

Question Stats:

72% (01:26) correct 28% (00:56) wrong based on 36 sessions

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A frame 2 inches wide is placed around a rectangular picture with dimensions 8 inches by 12 inches. What is the area of the frame, in square inches?

A. 44
B. 96
C. 128
D. 144
E. 168

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A frame 2 inches wide is placed around a rectangular picture with dime  [#permalink]

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Updated on: 12 Jan 2019, 04:05
Bunuel wrote:
A frame 2 inches wide is placed around a rectangular picture with dimensions 8 inches by 12 inches. What is the area of the frame, in square inches?

A. 44
B. 96
C. 128
D. 144
E. 168

total area of picture + frame = 12+2+2 * 8+2+2 = 16*12 = 192
and picture area = 12*8= 96
so area of fram = 192-96 = 96 IMO B
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Originally posted by Archit3110 on 11 Jan 2019, 04:38.
Last edited by Archit3110 on 12 Jan 2019, 04:05, edited 1 time in total.
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Re: A frame 2 inches wide is placed around a rectangular picture with dime  [#permalink]

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11 Jan 2019, 12:06
Area of photo=8*12=96
Area of photo+frame= (8+2+2)*(12+2+2)=12*16=192

Hence area of frame= 192-96=96
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Re: A frame 2 inches wide is placed around a rectangular picture with dime  [#permalink]

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11 Jan 2019, 12:15
IMo B

96

12+2+2=16*2=32 ×2=64
8*2=16*2=32

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Re: A frame 2 inches wide is placed around a rectangular picture with dime   [#permalink] 11 Jan 2019, 12:15
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