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I. 2v, 2w, 2x, 2y, 2z

Multiplication by 2 keeps the GP sequence intact

II. v + 2, w + 2, x + 2, y + 2, z + 2

Addition breaks the GP sequence in this case

III.\(\sqrt{v}, \sqrt{w}, \sqrt{x},\sqrt{y}, \sqrt{z}\)

Square rooting is nothing but changing the power from 1 to \(\frac{1}{2}\) ; it still keeps the GP sequence intact

Answer = E
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v, w, x, y, z
A geometric sequence is a sequence in which each term after
the first is equal to the product of the preceding term and a
constant. If the list of numbers shown above is an geometric
sequence, which of the following must also be a geometric
sequence?

I. 2v, 2w, 2x, 2y, 2z
II. v + 2, w + 2, x + 2, y + 2, z + 2
III.\sqrt{v}, \sqrt{w}, \sqrt{x},\sqrt{y}, \sqrt{z}

(A) I only
(B) II only
(C) III only
(D) I and II
(E) I and III

KUDOS please if you like my question.

We know that v,w,x,y,z are in GP. Thus, w/v = x/w = y/x = z/y = r(some constant, called the common ratio)

I. A multiplication by a constant (2) will not change the ratio, as evident.
III. The ratio for these terms will be another constant \(\sqrt{r}\)

E.

Let the common ratio of the terms in GP be r.
So, w = vr
x = vr^2
y = vr^3
z = vr^4

Now lets start checking I , II & III

I. 2v, 2w, 2x, 2y, 2z = 2v, 2vr, 2vr^2, 2vr^3, 2vr^4 Common ratio = r. So, GP
II. (v+2), (w+2), (x+2), (y+2), (z+2) = 2v+2, 2vr+2, 2vr^2 +2 , 2vr^3 +2, 2vr^4 +2 . Not in GP.
III. \(\sqrt{v},\sqrt{w},\sqrt{x},\sqrt{y},\sqrt{z}, = \sqrt{2v}, \sqrt{2vr}, \sqrt{2vr^2},\sqrt{2vr^3},\sqrt{2vr^4}\)

Common ration = \(\sqrt{r}\). So, GP

Answer E.
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what will happen if we choose negetive numbers in the series? eg-1,-2,-4,-8,-16? will option 3 still hold true?
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Let the numbers be -1, -3, -9, -27, -81 with r = 3
Check the option choices;
I. -2 , -6 , -18 , -54 ,-162 : GP with common ratio 3
II. 1 , -1 , -7 , -25 , -79 : Clearly not a G.P
III. Square root can’t be negative

Answer A.
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