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GMAT_700
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A geometry question from GMATPerp 06 May 2008, 17:29
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If you know how to solve this problem. Please let me know. Thanks!



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A geometry question from GMATPerp 06 May 2008, 17:44
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Easiest way I can think of is area of rectangle - area of 3 triangles around it:

Area of rectangle = \(7*4 = 28\)
Triangle 1 = \(1/2 * 4 * 3 = 6\)
Triangle 2 = \(1/2 * 3 *4 = 6\)
Triangle 3 = \(1/2 * 7 *1 = 3.5\)
Total triangles = \(15.5\)
Area of middle triangle = \(28 - 15.5 = 12.5\)

Let me know if there is a quicker way.
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A geometry question from GMATPerp 06 May 2008, 18:50
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Hi, there are several different ways this has been solved. This post covers a few of the ways.

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89nk
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A geometry question from GMATPerp 06 May 2008, 19:27
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bsd_lover
Easiest way I can think of is area of rectangle - area of 3 triangles around it:

Area of rectangle = \(7*4 = 28\)
Triangle 1 = \(1/2 * 4 * 3 = 6\)
Triangle 2 = \(1/2 * 3 *4 = 6\)
Triangle 3 = \(1/2 * 7 *1 = 3.5\)
Total triangles = \(15.5\)
Area of middle triangle = \(28 - 15.5 = 12.5\)

Let me know if there is a quicker way.
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This is how I solved it as well.
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AK79
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A geometry question from GMATPerp 06 May 2008, 20:35
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Just to add to the already great answers given...
Btw, I've had problems with this particular problem before, but for some reason, when I looked at it just now, a light went off :idea: :-D

Area of Triangle = bh/2

I made QP as the base, and PR as the height.
Draw 2 corresponding triangles with QP as the hypotenuse of triangle 1, and PR as the hypotenuse of the second.
The base for both triangles being the X axis.
You can quickly determine the length of the legs from the (x,y) coordinates.
Both of the drawn in triangles end up being 3-4-5
So the PR and QP have lengths of 5
= 5*5 / 2

Hope this helps as well..

Cheers,

AK
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A geometry question from GMATPerp 07 May 2008, 07:21
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GMAT_700
If you know how to solve this problem. Please let me know. Thanks!
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Very quick way to do in 20sec in ur head.

Just count the number of tics on the x axis to the the first point of the triangle: 4

Do the same for the y axis: 3. We can see that this new triangle is a 3,4,5. So one side of the drawn triangle is 5.

Same process for the other side from xaxis point (4,0) to (7,0). we have 3. then again for the Y axis a 0,4.

So we have another 3,4,5 triangle.

Now its just 5*5/2 = 12.5.



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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