|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
28 Jul 2021, 06:15
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
36% (03:19) correct
64%
(03:01)
wrong
based on 45
sessions
History
Date
Time
Result
Not Attempted Yet
A girl travels along a straight line, from point A to B at a constant speed, meters/sec for T seconds. Next, she travels from point B to C along a straight line, at a constant speed of meters/sec for another T seconds. BC makes an angle 105° with AB. If CA makes an angle 30° with BC, how much time will she take to travel back from point C to A at a constant speed of meters/sec, if she travels along a straight line from C to A?
A \(0.1(\sqrt{3} +1)T\)
B \(0.2(\sqrt{3} +1)T\)
C \(0.5(\sqrt{3} +1)T\)
D \(0.6(\sqrt{3} +1)T\)
E \((\sqrt{3} +1)T\)
A \(0.1(\sqrt{3} +1)T\)
B \(0.2(\sqrt{3} +1)T\)
C \(0.5(\sqrt{3} +1)T\)
D \(0.6(\sqrt{3} +1)T\)
E \((\sqrt{3} +1)T\)
28 Jul 2021, 19:27
Kudos
Bookmarks
Bunuel
We need one of the speeds to answer this question.
The graph for this question is fixed though. It is shown below and most importantly we need to draw BD perpendicular for AC to solve this question.
The two triangles would be 45-45-90 and 30-60-90 so every length can be solved with basic trig.
We can still figure out that AB and BC have a ratio of \(\sqrt{2}:2\), hence only one speed is needed.
Attachments
graph.png [ 18.27 KiB | Viewed 2795 times ]
yashikaaggarwal
Senior Moderator - Masters Forum
Joined: 19 Jan 2020
Last visit: 29 Mar 2026
Posts: 3,088
Own Kudos:
Given Kudos: 1,510
Location: India
Schools: Cranfield (A) Warwick MiM "23 (M)
GPA: 4
WE:Analyst (Internet and New Media)
01 Aug 2021, 06:53
Kudos
Bookmarks
TestPrepUnlimited
Is there any easy way to solve this? I couldn't even comprehend the question.
