A glucose molecule contains 6 carbon, 12 hydrogen and 6 oxygen atoms.

Question

Tough and Tricky questions: Word Problems.

A glucose molecule contains 6 carbon, 12 hydrogen and 6 oxygen atoms. During photosynthesis, green plants create glucose daily. If, over a period of 10 days, an eucalyptus plant (a green plant) creates 10,000 molecules of glucose then approximately how many more atoms of hydrogen than carbon are created on average per day?

A. 60,000
B. 6,000
C. 2,500
D. 250
E. 0

Kudos for a correct  solution .

g106 · Answer

1 G molecule = 6C 12H 6)
for 10000 G = 60000C 120000H 60000 O

so 60000 more H atoms for 10 days = 6000 atoms per day

Ans B

PareshGmat · Answer

Answer = B. 6,000

Average per day  = \frac{10000}{10} = 1000

Hydrogen per day = 1000*12 = 12000

Carbon per day = 1000*6 = 6000

Difference = 6000

jayanth7290 · Answer

From the q its clear that

No of hydrogen atoms more than carbon atoms per molecule = 6 .

Per day 1000 molecules r produced

No of hydrogen atoms more than carbon for 1000 molecules is = 6*1000 = 6000  (Y)

DesiGmat · Answer

1 Molecule contains 12 hydrogen atoms and 6 carbon atoms.
hence Hydrogen - Carbon = 6 per molecule

In 10 days, 10,000 molecules were created-> Hence difference is 60,000 for 10 days-> 6000 per day

Correct Answer is B

Bunuel · Answer

OFFICIAL SOLUTION:

(B) 10,000 glucose molecules are created over a period of 10 days. Therefore 10,000/10 = 1,000 glucose molecules are created on average per day.

Each glucose molecule contains 6 carbon atoms and 12 hydrogen atoms. So 1,000 glucose molecules contain 6 × 1,000 = 6,000 carbon atoms and 12 × 1,000 = 12,000 hydrogen atoms. The difference is 12,000 – 6,000 = 6,000.

The correct answer is B.

bumpbot · Answer

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A glucose molecule contains 6 carbon, 12 hydrogen and 6 oxygen atoms.

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A glucose molecule contains 6 carbon, 12 hydrogen and 6 oxygen atoms.

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