GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 18 Oct 2019, 06:39

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

A group consists of both men and women. The average (arithmetic mean)

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Find Similar Topics 
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 58453
A group consists of both men and women. The average (arithmetic mean)  [#permalink]

Show Tags

New post 30 Aug 2018, 00:31
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

66% (01:07) correct 34% (01:26) wrong based on 51 sessions

HideShow timer Statistics

A group consists of both men and women. The average (arithmetic mean) height of the women is 66 inches, and the average (arithmetic mean) height of the men is 72 inches. If the average (arithmetic mean) height of all the people in the group is 70 inches, what is the ratio of women to men in the group?

(A) 1:1
(B) 1:2
(C) 2:1
(D) 2:3
(E) 3:2

_________________
Intern
Intern
avatar
Joined: 30 Aug 2018
Posts: 4
Re: A group consists of both men and women. The average (arithmetic mean)  [#permalink]

Show Tags

New post 30 Aug 2018, 00:57
C. 2:1
(66x + 72y)/(x+y) = 70
66x + 72y =70x + 70y
66x-70x = 70y-72y
-4x=-2y
2:1

Posted from my mobile device
Intern
Intern
avatar
Joined: 30 Aug 2018
Posts: 4
Re: A group consists of both men and women. The average (arithmetic mean)  [#permalink]

Show Tags

New post 30 Aug 2018, 00:58
C. 2:1
(66x + 72y)/(x+y) = 70
66x + 72y =70x + 70y
66x-70x = 70y-72y
-4x=-2y
2:1

Posted from my mobile device
VP
VP
User avatar
D
Status: Learning stage
Joined: 01 Oct 2017
Posts: 1013
WE: Supply Chain Management (Energy and Utilities)
Re: A group consists of both men and women. The average (arithmetic mean)  [#permalink]

Show Tags

New post 30 Aug 2018, 01:05
1
Bunuel wrote:
A group consists of both men and women. The average (arithmetic mean) height of the women is 66 inches, and the average (arithmetic mean) height of the men is 72 inches. If the average (arithmetic mean) height of all the people in the group is 70 inches, what is the ratio of women to men in the group?

(A) 1:1
(B) 1:2
(C) 2:1
(D) 2:3
(E) 3:2


Sum of heights of women=66*w
Sum of heights of men=72*m
Sum of heights of the group(men+women)= 70*(m+w)

To find:- w:m=?

Now, Sum of height of men+sum of height of women=Sum of heights of the group
or, 66w+72m=70*(m+w)
or, 2m=4w
Or, w:m=1:2

Ans. (B)
_________________
Regards,

PKN

Rise above the storm, you will find the sunshine
VP
VP
User avatar
D
Joined: 31 Oct 2013
Posts: 1464
Concentration: Accounting, Finance
GPA: 3.68
WE: Analyst (Accounting)
CAT Tests
Re: A group consists of both men and women. The average (arithmetic mean)  [#permalink]

Show Tags

New post 30 Aug 2018, 06:20
1
Bunuel wrote:
A group consists of both men and women. The average (arithmetic mean) height of the women is 66 inches, and the average (arithmetic mean) height of the men is 72 inches. If the average (arithmetic mean) height of all the people in the group is 70 inches, what is the ratio of women to men in the group?

(A) 1:1
(B) 1:2
(C) 2:1
(D) 2:3
(E) 3:2


Using Allegation Method , one can solve this question in 20 sec...........
Attachments

Untitled1.png
Untitled1.png [ 14.84 KiB | Viewed 708 times ]

Board of Directors
User avatar
D
Status: QA & VA Forum Moderator
Joined: 11 Jun 2011
Posts: 4771
Location: India
GPA: 3.5
WE: Business Development (Commercial Banking)
GMAT ToolKit User
Re: A group consists of both men and women. The average (arithmetic mean)  [#permalink]

Show Tags

New post 30 Aug 2018, 06:41
Bunuel wrote:
A group consists of both men and women. The average (arithmetic mean) height of the women is 66 inches, and the average (arithmetic mean) height of the men is 72 inches. If the average (arithmetic mean) height of all the people in the group is 70 inches, what is the ratio of women to men in the group?

(A) 1:1
(B) 1:2
(C) 2:1
(D) 2:3
(E) 3:2

\(66w + 72m = 70m + 70w\)

Or, \(4w = 2m\)

Or, \(w : m = 1 : 2\), Answer must be (B)
_________________
Thanks and Regards

Abhishek....

PLEASE FOLLOW THE RULES FOR POSTING IN QA AND VA FORUM AND USE SEARCH FUNCTION BEFORE POSTING NEW QUESTIONS

How to use Search Function in GMAT Club | Rules for Posting in QA forum | Writing Mathematical Formulas |Rules for Posting in VA forum | Request Expert's Reply ( VA Forum Only )
VP
VP
User avatar
D
Joined: 09 Mar 2016
Posts: 1230
A group consists of both men and women. The average (arithmetic mean)  [#permalink]

Show Tags

New post 30 Aug 2018, 07:08
Bunuel wrote:
A group consists of both men and women. The average (arithmetic mean) height of the women is 66 inches, and the average (arithmetic mean) height of the men is 72 inches. If the average (arithmetic mean) height of all the people in the group is 70 inches, what is the ratio of women to men in the group?

(A) 1:1
(B) 1:2
(C) 2:1
(D) 2:3
(E) 3:2


let #number of males be M
let #number of females be F
let number of all people be X

average (arithmetic mean) height of the women is 66 inches \(\frac{X}{F} = 66\) --- > X= 66F (1)

average (arithmetic mean) height of the men is 72 inches \(\frac{X}{M}= 72\) ---- > X=72M (2)

average (arithmetic mean) height of all the people in the group is 70 inches \(\frac{X}{M+F} = 70\) (plug in X1 and X2 here :) )


\(\frac{66F+72M}{M+F} = 70\)

\(66F+72M = 70(M+F)\)

\(66F+72M = 70M+70F\)

\(2M=4F\)

\(1M=2F\)
VP
VP
User avatar
D
Joined: 09 Mar 2016
Posts: 1230
Re: A group consists of both men and women. The average (arithmetic mean)  [#permalink]

Show Tags

New post 30 Aug 2018, 07:11
selim wrote:
Bunuel wrote:
A group consists of both men and women. The average (arithmetic mean) height of the women is 66 inches, and the average (arithmetic mean) height of the men is 72 inches. If the average (arithmetic mean) height of all the people in the group is 70 inches, what is the ratio of women to men in the group?

(A) 1:1
(B) 1:2
(C) 2:1
(D) 2:3
(E) 3:2


Using Allegation Method , one can solve this question in 20 sec...........



thanks for reminding me alligator method :)
GMAT Club Bot
Re: A group consists of both men and women. The average (arithmetic mean)   [#permalink] 30 Aug 2018, 07:11
Display posts from previous: Sort by

A group consists of both men and women. The average (arithmetic mean)

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  





cron

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne