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A group of children start a mowing and raking team called Gardening

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GMAT 1: 670 Q46 V36
A group of children start a mowing and raking team called Gardening  [#permalink]

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New post 03 Jul 2018, 18:28
3
00:00
A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

67% (03:36) correct 33% (02:32) wrong based on 39 sessions

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A group of children start a mowing and raking team called Gardening Guys that services one neighborhood house a day for 21 days. Each day, Gardening Guys receives $50 for their services and divides it equally between all the children who serviced the house that day. For one week (7 days), 3 children on the team go to camp and can’t work on the team, but they work every day they are not in camp. Everyone else works on the team every day. If there are k total children in Gardening Guys, where k > 3, how much will Lamar, who does not go to camp, make from working on the team?

A. \(\frac{1050}{k(k-2)(k-3)}\)
B. \(\frac{1050k}{(k-3)}\)
C. \(\frac{1050(k-3)}{k(k-2)}\)
D. \(\frac{1050}{k(k-3)}\)
E. \(\frac{1050(k-2)}{k(k-3)}\)

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Re: A group of children start a mowing and raking team called Gardening  [#permalink]

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New post 03 Jul 2018, 20:01
50*14/k+350/(k-3)
IMO answer E
Is really 700 level question?
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Re: A group of children start a mowing and raking team called Gardening  [#permalink]

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New post 05 Jul 2018, 16:16
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dabaobao wrote:
A group of children start a mowing and raking team called Gardening Guys that services one neighborhood house a day for 21 days. Each day, Gardening Guys receives $50 for their services and divides it equally between all the children who serviced the house that day. For one week (7 days), 3 children on the team go to camp and can’t work on the team, but they work every day they are not in camp. Everyone else works on the team every day. If there are k total children in Gardening Guys, where k > 3, how much will Lamar, who does not go to camp, make from working on the team?

A. \(\frac{1050}{k(k-2)(k-3)}\)
B. \(\frac{1050k}{(k-3)}\)
C. \(\frac{1050(k-3)}{k(k-2)}\)
D. \(\frac{1050}{k(k-3)}\)
E. \(\frac{1050(k-2)}{k(k-3)}\)


Let k=4. implying a total of 4 children.

On the 14 non-camp days when all 4 children work, Lamar earns \(\frac{1}{4}\) of the total earnings.
Since $50 is earned for each of these 14 days, we get:
Lamar's share = \(\frac{1}{4} * 50 * 14 = 175\).

On the 7 camp days when 3 of the 4 children attend camp and Lamar works alone, Lamar earns the entire $50 per day, for a 7-day total of $350.

Thus:
Total earned by Lamar = \(175+350=525\).

The correct answer must yield $525 when k=4.
Only E works:
\(\frac{1050(k-2)}{k(k-3)} = \frac{1050(4-2)}{4(4-3)} = 1050(\frac{2}{4}) = 1050(\frac{1}{2}) = 525\)


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Re: A group of children start a mowing and raking team called Gardening &nbs [#permalink] 05 Jul 2018, 16:16
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