Bunuel wrote:

A group of n college students bought three identical round cakes to share. They divided the first cake into equal-sized pieces, one piece for each of them. They did the same with the second cake. After 3 of the students decided they did not want any more cake, the remaining students divided the third cake into equal-sized pieces, one piece for each of them. If Silvia received 1 piece from each of the three cakes, then, in terms of n, the amount of cake that she received was the same as what fraction of 1 cake?

A. \(\frac{n+2}{n(n−3)}\)

B. \(\frac{2n−3}{n(n−3)}\)

C. \(\frac{3n−3}{n(n−3)}\)

D. \(\frac{3n−6}{n(n−3)}\)

E. \(\frac{3n−3}{2n(n−3)}\)

GMATinsight :

Sir I did not understand the last line of the question "in terms of n,

the amount of cake that she received was the same as what fraction of 1 cake?I did the following way let n be 9

so cake 1 ; 9 pieces

Cake 2 : 9 pieces

Cake 3 : 6 pieces

total pieces received by Silvia is 3

total cake pieces : 9+9+6= 24

1/9+1/9+1/6= 7/18

i.e. option D suffices this relation

Since I am not able to understand what is exactly to be derived so I am not able to find the correct answer option.. please help ....

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