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A group of store managers must assemble 280 displays for an upcoming sale. If they assemble 25 percent of the displays during the first hour and 40 percent of the remaining displays during the second hour, how many of the displays will not have been assembled by the end of the second hour?
(A) 70 (B) 98 (C) 126 (D) 168 (E) 182
Problem Solving Question: 159 Category:Arithmetic Percents Page: 83 Difficulty: 600
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Re: A group of store managers must assemble 280 displays for an
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13 Mar 2014, 02:27
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SOLUTION
A group of store managers must assemble 280 displays for an upcoming sale. If they assemble 25 percent of the displays during the first hour and 40 percent of the remaining displays during the second hour, how many of the displays will not have been assembled by the end of the second hour?
(A) 70 (B) 98 (C) 126 (D) 168 (E) 182
During the first hour 0.25*280 = 70 displays were assembled. During the second hour 0.4*(280-70) = 84 displays were assembled.
Thus, 280 - (70+84) = 126 displays had not been assembled by the end of the second hour.
Re: A group of store managers must assemble 280 displays for an
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17 Jul 2014, 21:17
Another way to solve this is 25% + 30% (40% of 100-25) = 55% of displays were assembled. So number of displays that were not assembled = 45% of 280 = 126.
Re: A group of store managers must assemble 280 displays for an
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29 Jul 2016, 10:51
displays assembled in the first hour => 1/4*280=70 in the second hour => 40/100*210=> 84 Displays not assembled => 280-(70+84)=> 126 Smash C
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Re: A group of store managers must assemble 280 displays for an
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18 Jun 2019, 12:34
The alternate method could be
In first hour they did 25 % , So remaining is 75%. and in second hour they did 40% of 75% means 10% is 7.5 then 40 % is 30 % So in two hours they assembled 55% of stuff. and 45 % is yet to be done So 45% of 280 is what that is 126
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Probus
~You Just Can't beat the person who never gives up~ Babe Ruth
A group of store managers must assemble 280 displays for an upcoming sale. If they assemble 25 percent of the displays during the first hour and 40 percent of the remaining displays during the second hour, how many of the displays will not have been assembled by the end of the second hour?