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A group of store managers must assemble 280 displays for an

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A group of store managers must assemble 280 displays for an [#permalink]

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The Official Guide For GMAT® Quantitative Review, 2ND Edition

A group of store managers must assemble 280 displays for an upcoming sale. If they assemble 25 percent of the displays during the first hour and 40 percent of the remaining displays during the second hour, how many of the displays will not have been assembled by the end of the second hour?

(A) 70
(B) 98
(C) 126
(D) 168
(E) 182

Problem Solving
Question: 159
Category: Arithmetic Percents
Page: 83
Difficulty: 600


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Re: A group of store managers must assemble 280 displays for an [#permalink]

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A group of store managers must assemble 280 displays for an upcoming sale. If they assemble 25 percent of the displays during the first hour and 40 percent of the remaining displays during the second hour, how many of the displays will not have been assembled by the end of the second hour?

(A) 70
(B) 98
(C) 126
(D) 168
(E) 182

During the first hour 0.25*280 = 70 displays were assembled.
During the second hour 0.4*(280-70) = 84 displays were assembled.

Thus, 280 - (70+84) = 126 displays had not been assembled by the end of the second hour.

Answer: C.
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Re: A group of store managers must assemble 280 displays for an [#permalink]

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New post 13 Mar 2014, 19:20
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Answer = (C) 126

In first hour, 25% of 280 = 70

Remaining = 210

40 percent of the remaining displays during the second hour, how many of the displays will not have been assembled by the end of the second hour?

Means 60% have not been assembled

So 60% of 210 = 126
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Re: A group of store managers must assemble 280 displays for an [#permalink]

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New post 20 May 2014, 13:35
Total Displays:280

Remaining after first hr: 280*75/100

Remaining after 2nd hr: 280*75/100*60/100 = 126

280*75/100*60/100 = 126
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Re: A group of store managers must assemble 280 displays for an [#permalink]

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Total number of displays to be assembled = 280

After one hour , 25% were assembled.

Remaining (75%) = 75% of 280 = 210

40% of remaining displays assembled in second hour. Remaining 60% = 60% of 210 = 126

Hence C.
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Re: A group of store managers must assemble 280 displays for an [#permalink]

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New post 17 Jul 2014, 21:17
Another way to solve this is 25% + 30% (40% of 100-25) = 55% of displays were assembled. So number of displays that were not assembled = 45% of 280 = 126.

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Re: A group of store managers must assemble 280 displays for an [#permalink]

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New post 29 Jul 2016, 10:51
displays assembled in the first hour => 1/4*280=70
in the second hour => 40/100*210=> 84
Displays not assembled => 280-(70+84)=> 126
Smash C
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Re: A group of store managers must assemble 280 displays for an [#permalink]

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Re: A group of store managers must assemble 280 displays for an   [#permalink] 26 Sep 2017, 15:53
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