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A hat contains 12 cards marked with a star and 18 unmarked cards. What

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A hat contains 12 cards marked with a star and 18 unmarked cards. What [#permalink]

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New post 19 Apr 2017, 01:36
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88% (00:23) correct 12% (00:40) wrong based on 97 sessions

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A hat contains 12 cards marked with a star and 18 unmarked cards. What is the probability that one card selected at random will be marked with a star?

A. 2/5
B. 3/5
C. 2/3
D. 3/2
E. 5/2

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Re: A hat contains 12 cards marked with a star and 18 unmarked cards. What [#permalink]

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New post 19 Apr 2017, 06:40
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Bunuel wrote:
A hat contains 12 cards marked with a star and 18 unmarked cards. What is the probability that one card selected at random will be marked with a star?

A. 2/5
B. 3/5
C. 2/3
D. 3/2
E. 5/2


We can solve this by applying the general probability formula:
P(event A occurs) = (# of outcomes where event A occurs)/(total # of outcomes)

So, P(marked card) = (# of outcomes in which we get a marked card)/(total # of outcomes)

There are 12 marked cards. So, there are 12 possible outcomes in which we get a marked card

There are 30 cards altogether (12 marked + 18 unmarked = 30 in total). So, there are 30 possible outcomes.

So, P(marked card) = 12/30
= 2/5

Answer:

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Re: A hat contains 12 cards marked with a star and 18 unmarked cards. What [#permalink]

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New post 24 Apr 2017, 17:12
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Bunuel wrote:
A hat contains 12 cards marked with a star and 18 unmarked cards. What is the probability that one card selected at random will be marked with a star?

A. 2/5
B. 3/5
C. 2/3
D. 3/2
E. 5/2


Since there are a total of 30 cards and 12 that are marked with stars, the probability of selecting a card marked with a star is 12/30 = 2/5.

Answer: A
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Re: A hat contains 12 cards marked with a star and 18 unmarked cards. What   [#permalink] 24 Apr 2017, 17:12
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