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A laborer is paid $8 per hour for an 8-hour day and 3/2 times that rat

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A laborer is paid $8 per hour for an 8-hour day and 3/2 times that rat  [#permalink]

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New post 05 Feb 2018, 06:38
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Question Stats:

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A laborer is paid $8 per hour for an 8-hour day and 3/2 times that rate for each hour in excess of 8 hours in a single day. If the laborer received $80 for a single day's work, how long did he work on that day?

(A) 6 hr. 40 min.

(B) 9 hr. 20 min.

(C) 9 hr. 30 min.

(D) 9 hr. 40 min.

(E) 10 hr.

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A laborer is paid $8 per hour for an 8-hour day and 3/2 times that rat  [#permalink]

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New post 05 Feb 2018, 07:31
Bunuel wrote:
A laborer is paid $8 per hour for an 8-hour day and 3/2 times that rate for each hour in excess of 8 hours in a single day. If the laborer received $80 for a single day's work, how long did he work on that day?

(A) 6 hr. 40 min.

(B) 9 hr. 20 min.

(C) 9 hr. 30 min.

(D) 9 hr. 40 min.

(E) 10 hr.


We are told that the laborer is paid $8 per hour for the first 8 hours.
As he is paid \(\frac{3}{2}\) the rate for the next few hours, he will get paid \(\frac{3}{2}*8 = $12\) for the remaining hours.

Since he is paid $80, the total number of hours can be calculated as follows

\($8*8 + $12*x = $80\) -> x = \(\frac{16}{12}\) -> x=\(\frac{4}{3} = 1\frac{1}{3}\) hours

Converting into minutes - 1 hour 20 minutes.

Therefore, the total time that the laborer works is 9 hour 20 minutes(Option B)
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A laborer is paid $8 per hour for an 8-hour day and 3/2 times that rat  [#permalink]

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New post 05 Feb 2018, 18:39
Bunuel wrote:
A laborer is paid $8 per hour for an 8-hour day and 3/2 times that rate for each hour in excess of 8 hours in a single day. If the laborer received $80 for a single day's work, how long did he work on that day?

(A) 6 hr. 40 min.

(B) 9 hr. 20 min.

(C) 9 hr. 30 min.

(D) 9 hr. 40 min.

(E) 10 hr.

Normal wage = $8 per hour
Overtime wage = $8 *\(\frac{3}{2}\) = $12 per hour

The laborer received $80 for one day.
Normal day's pay: (8 hours * $8 per hr) = $64
Extra PAY for that day: $80 - $64 = $16

Normal day = 8 hours
Extra hours?
\(\frac{TotalAmountExtra}{AmountPerHour}\) = number of extra hours

\(\frac{$16}{$12} = \frac{4}{3} = 1\frac{1}{3}\) hours extra

Total HOURS? 8 + 1 = 9

MINUTES? Multiply any fraction of an hour to calculate minutes
\(\frac{1}{3} * 60 = 20\) minutes

Total time worked: 9 hours, 20 minutes

Answer B
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A laborer is paid $8 per hour for an 8-hour day and 3/2 times that rat  [#permalink]

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New post 05 Feb 2018, 19:57
Confused with option B and C
As the HR is not completed would the standard rate apply or the increased rate apply?

Would chose B


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A laborer is paid $8 per hour for an 8-hour day and 3/2 times that rat  [#permalink]

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New post 05 Feb 2018, 20:45
MT1988 wrote:
Confused with option B and C
As the HR is not completed would the standard rate apply or the increased rate apply?

Would chose B


Sent from my iPhone using GMAT Club Forum

MT1988 , as soon as the laborer meets the condition that allows him to receive increased (not standard) pay, he receives the increased pay rate for the rest of that day.

The condition -- the event that raises his hourly wage for the rest of that day -- is not whether any single hour is over.

The condition is in the question.

Hope that helps. :-)
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Re: A laborer is paid $8 per hour for an 8-hour day and 3/2 times that rat  [#permalink]

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New post 06 Feb 2018, 18:32
Bunuel wrote:
A laborer is paid $8 per hour for an 8-hour day and 3/2 times that rate for each hour in excess of 8 hours in a single day. If the laborer received $80 for a single day's work, how long did he work on that day?

(A) 6 hr. 40 min.

(B) 9 hr. 20 min.

(C) 9 hr. 30 min.

(D) 9 hr. 40 min.

(E) 10 hr.


We can create the following equation in which n = the number of hours worked and (n - 8) is the number of hours worked in excess of 8 hours:

80 = 8(8) + (8 x 3/2)(n - 8)

80 = 64 + 12(n - 8)

16 = 12n - 96
112 = 12n

112/12 = 28/3 = 9 1/3 hours = 9 hours and 20 minutes

Answer: B
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Re: A laborer is paid $8 per hour for an 8-hour day and 3/2 times that rat &nbs [#permalink] 06 Feb 2018, 18:32
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