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Math Expert
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Re: A lawn care company has five employees that it schedules on a given da [#permalink]
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IT IS A PERMUTATION PROBLEM. HOW MANY WAYS 5 PEOPLE CAN BE ASSIGNED TO 10 HOMES. YOU HAVE BEEN ASKED TO ARRANGE THOSE 5 PEOPLE SO ITS 10P5= 10!/5!( derived from the formula nPr= n!/(n-r)!)

You can also solve this problem by using the normal arrangement method.

The first dude can work on any of the 10 lawns , the second has 9 choices since the first has taken one for him. Similarly, the third, fourth and fifth dude has 8, 7 and 6 choices of lawns to choose from. So the different ways the company can assign work to these 5 employees are 10*9*8*7*6 = 10!/5!

ANS D is the right answer choice
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Re: A lawn care company has five employees that it schedules on a given da [#permalink]
A lawn care company has five employees that it schedules on a given day to work the lawns of any ten possible homes. How many different ways can the company assign the five employees to the ten homes if each employee provides lawn care service for just one home?
Sol=> Firstly we will select 5 out of the ten lawns and since every employee works only on one lawn we will distribute the workers to the five lawns so the number of ways in which this process can be done is---
(10C5) * 5! = (10!/5!5!)*5! = 10!/5!
Hence option D
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Re: A lawn care company has five employees that it schedules on a given da [#permalink]
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