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A line that passes through (–1, –4) and (3, k) has a slope = k. What [#permalink]
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19 Nov 2012, 17:30
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A line that passes through (–1, –4) and (3, k) has a slope = k. What is the value of k?
(A) 3/4 (B) 1 (C) 4/3 (D) 2 (E) 7/2See a full discussion of lines & slope in the xy plane here: http://magoosh.com/gmat/2012/gmatmath ... xyplane/Experts: feel free to add any other xy plane advice you would like to share.
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Re: A line that passes through (–1, –4) and (3, k) has a slope = k. What [#permalink]
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19 Nov 2012, 18:35
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mikemcgarry wrote: A line that passes through (–1, –4) and (3, k) has a slope = k. What is the value of k? (A) 3/4 (B) 1 (C) 4/3 (D) 2 (E) 7/2See a full discussion of lines & slope in the xy plane here: http://magoosh.com/gmat/2012/gmatmath ... xyplane/Experts: feel free to add any other xy plane advice you would like to share. Slope = (y2y1)/(x2x1) => k = (k+4)/(3+1) => 4k = k+4 => k =4/3 Ans C it is!
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Re: A line that passes through (–1, –4) and (3, k) has a slope = k. What [#permalink]
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29 Nov 2012, 11:32
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y=mx+c is the equation. Since the line passes through (1,4) and (3,k) substitute this for the value of x and y. we get 2 equations 4=k+c...(1) c=2k.......(2) Substitute for C in equation 1. we get k=4/3. The ans is C.
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Re: A line that passes through (–1, –4) and (3, k) has a slope = k. What [#permalink]
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07 Dec 2012, 04:43
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A line that passes through (–1, –4) and (3, k) has a slope = k. What is the value of k? m = \(\frac{y2y1}{x2x1}\) m = \(\frac{k(4)}{3(1)}\) m = \(\frac{k+4}{4}\) & \(m = k\) \(k = \frac{k+4}{4}\) \(4k = k+4\) \(k = 4/3\) Answer: 4/3
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Re: A line that passes through (–1, –4) and (3, k) has a slope = k. What [#permalink]
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04 Mar 2015, 04:10



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Re: A line that passes through (–1, –4) and (3, k) has a slope = k. What [#permalink]
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04 Mar 2015, 10:50
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(k+4)/(3+1)=(k+4)/4 this is the slope of the line
we also know that slope=k, then respectively
k=(k+4)/4 4k=k+4 k=4/3
Answ C



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Re: A line that passes through (–1, –4) and (3, k) has a slope = k. What [#permalink]
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04 Mar 2015, 12:57
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Answer Is C....
Since 2 points are given and we are told that a line passes through points (1, 4) & ( 3,k) , so we have simple formula to line's slope.
slope = ( y2 y1)/ (x2x1) Or : ( k(4) ) / ( 3(1)) = k+4/ 4 and we are told that this is equal to k
so we have : k+4/4 =k and multiple both sides by 4 and get : k+4 = 4k or 3 k=4 so , k= 4/3 answer c...



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Re: A line that passes through (–1, –4) and (3, k) has a slope = k. What [#permalink]
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08 Mar 2015, 14:13
Bunuel wrote: A line that passes through (–1, –4) and (3, k) has a slope = k. What is the value of k?
A. 3/4 B. 1 C. 4/3 D. 2 E. 7/2
Kudos for a correct solution. MAGOOSH OFFICIAL SOLUTION:This is a considerably more difficult one, which will involve some algebra. Let’s say that the “first” point is (–1, –4) and the “second,” (3, k). The rise = k + 4, which involves a variable. The run = 3 – (–1) = 4. There the slope is (k + 4)/4, and we can set this equal to k and solve for k. (k + 4)/4 = k k + 4 = 4k 4 = 3k k = 4/3 Answer = C
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Re: A line that passes through (–1, –4) and (3, k) has a slope = k. What [#permalink]
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14 Jul 2016, 04:47
Slope = Delta y/Delta x \(k=\frac{k(4)}{3(1)} ===>k= \frac{k+4}{4} ===>4k=k+4 ==>3k=4\)therefore \(k=\frac{4}{3}\) Answer C Bunuel wrote: A line that passes through (–1, –4) and (3, k) has a slope = k. What is the value of k?
A. 3/4 B. 1 C. 4/3 D. 2 E. 7/2
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Re: A line that passes through (–1, –4) and (3, k) has a slope = k. What [#permalink]
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Re: A line that passes through (–1, –4) and (3, k) has a slope = k. What
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