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Re: A line that passes through (–1, –4) and (3, k) has a slope = k. What
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29 Nov 2012, 11:32
1
y=mx+c is the equation. Since the line passes through (-1,-4) and (3,k) substitute this for the value of x and y.
we get 2 equations
-4=-k+c...(1) c=-2k.......(2)
Substitute for C in equation 1. we get k=4/3.
The ans is C.
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This is a considerably more difficult one, which will involve some algebra. Let’s say that the “first” point is (–1, –4) and the “second,” (3, k). The rise = k + 4, which involves a variable. The run = 3 – (–1) = 4. There the slope is (k + 4)/4, and we can set this equal to k and solve for k. (k + 4)/4 = k k + 4 = 4k 4 = 3k k = 4/3
A line that passes through (–1, –4) and (3, k) has a slope = k. What is the value of k?
A. 3/4 B. 1 C. 4/3 D. 2 E. 7/2
Kudos for a correct solution.
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Re: A line that passes through (–1, –4) and (3, k) has a slope = k. What
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28 Oct 2017, 06:34
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84% (01:11) correct 
