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30 Jun 2012, 23:45
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
44% (02:24) correct
56%
(02:16)
wrong
based on 279
sessions
History
Date
Time
Result
Not Attempted Yet
A man sets out to cycle from BBSR to CTC and at the same time another man starts from CTC to BBSR. After passing each other they complete their journeys in 4 and 9 hrs respectively. At what rate does the second man cycle if the first one cycles at 9 km/hr.
A. 4 km/hr
B. 6 km/hr
C. 8 km/hr
D. 9 km/hr
E. can't be determined
A. 4 km/hr
B. 6 km/hr
C. 8 km/hr
D. 9 km/hr
E. can't be determined
BukrsGmat
You can use the formula or the ratio approach.
Formula:
If two objects A and B start simultaneously from opposite points and, after meeting, reach their destinations in ‘a’ and ‘b’ hours respectively (i.e. A takes ‘a hrs’ to travel from the meeting point to his destination and B takes ‘b hrs’ to travel from the meeting point to his destination), then the ratio of their speeds is given by:
\(Sa/Sb = \sqrt{(b/a)} = \sqrt{9/4} = 3/2\)
So the ratio of speeds of first man and second man is 3:2
If the first man cycles at 9 km/hr (which is 3*3), the second will cycle at 2*3 = 6 km/hr
General Discussion
01 Jul 2012, 02:01
Kudos
Bookmarks
sujit2k7
Hi,
let the speed of second person by x,
and the time taken by them to meet is t,
also, we know that speed of first person is 9km/hr
(BBSR)A------------------------C---------------B(CTC)
supposing they meet at C,
so, distance traveled by first person in t time = distance traveled by second person in 9hrs (=AC)
or 9t=x*9
or x = t
similarly, distance traveled by second person in t time = distance traveled by second person in 4hrs (=CB)
or x*t = 9*4
or \(x^2=36\)
or x=6km/hr
Answer is (B)
Regards,
