sujit2k7 wrote:
A man sets out to cycle from BBSR to CTC and at the same time another man starts from CTC to BBSR. After passing each other they complete their journeys in 4 and 9 hrs respectively . At what rate does the second man cycle if the first one cycles at 9 km/hr.
a) 4km/hr
b) 6km/hr
c) 8 km/hr
d) 9 km/hr
e) can't be determined
Hi,
let the speed of second person by x,
and the time taken by them to meet is t,
also, we know that speed of first person is 9km/hr
(BBSR)A------------------------C---------------B(CTC)
supposing they meet at C,
so, distance traveled by first person in t time = distance traveled by second person in 9hrs (=AC)
or 9t=x*9
or x = t
similarly, distance traveled by second person in t time = distance traveled by second person in 4hrs (=CB)
or x*t = 9*4
or \(x^2=36\)
or x=6km/hr
Answer is (B)
Regards,