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# A man travels a distance of 20 miles at 60 miles per hour and then re

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Math Expert
Joined: 02 Sep 2009
Posts: 44282
A man travels a distance of 20 miles at 60 miles per hour and then re [#permalink]

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01 Mar 2018, 00:43
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A man travels a distance of 20 miles at 60 miles per hour and then returns over the same route at 40 miles per hour. What is his average rate for the round trip in miles per hour?

(A) 50

(B) 48

(C) 47

(D) 46

(E) 45
[Reveal] Spoiler: OA

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Intern
Joined: 31 Oct 2013
Posts: 29
Re: A man travels a distance of 20 miles at 60 miles per hour and then re [#permalink]

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01 Mar 2018, 04:05
Bunuel wrote:
A man travels a distance of 20 miles at 60 miles per hour and then returns over the same route at 40 miles per hour. What is his average rate for the round trip in miles per hour?

(A) 50

(B) 48

(C) 47

(D) 46

(E) 45

Average speed for the round trip : 2.x.y/x+y
=2.40.60/40+60
=2.40.60/10
=48
VP
Joined: 22 May 2016
Posts: 1416
A man travels a distance of 20 miles at 60 miles per hour and then re [#permalink]

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01 Mar 2018, 10:08
Bunuel wrote:
A man travels a distance of 20 miles at 60 miles per hour and then returns over the same route at 40 miles per hour. What is his average rate for the round trip in miles per hour?

(A) 50

(B) 48

(C) 47

(D) 46

(E) 45

Average speed = $$\frac{TotalDistance}{TotalTime}$$

RT = D
T = D/R

Total time = (Leg 1 + Leg 2)

Leg 1 time = $$\frac{20}{60}=\frac{1}{3}$$ hour

Leg 2 time = $$\frac{20}{40}=\frac{1}{2}$$ hour

Total time: $$\frac{1}{3} +\frac{1}{2}=\frac{5}{6}$$ hour

Total Distance = (20mi + 20mi) = 40 miles

Ave speed*: $$\frac{40}{(\frac{5}{6})}=40 *\frac{6}{5}=48$$
mph

*With units. If you stay with time in hours, then you don't need units, but that fact may not be obvious.
$$\frac{40miles}{(\frac{5}{6}hour)}=40miles *\frac{6}{5hrs}=48\frac{miles}{hour}=48$$ mph

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Re: A man travels a distance of 20 miles at 60 miles per hour and then re [#permalink]

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02 Mar 2018, 10:36
Bunuel wrote:
A man travels a distance of 20 miles at 60 miles per hour and then returns over the same route at 40 miles per hour. What is his average rate for the round trip in miles per hour?

(A) 50

(B) 48

(C) 47

(D) 46

(E) 45

We can use the following formula:

average = (total distance)/(total time)

Average = 40/(20/60 + 20/40)

Average = 40/(1/3 + 1/2)

Average = 40/(2/6 + 3/6)

Average = 40/(5/6) = 240/5 = 48

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Re: A man travels a distance of 20 miles at 60 miles per hour and then re [#permalink]

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02 Mar 2018, 10:54
Bunuel wrote:
A man travels a distance of 20 miles at 60 miles per hour and then returns over the same route at 40 miles per hour. What is his average rate for the round trip in miles per hour?

(A) 50

(B) 48

(C) 47

(D) 46

(E) 45

Average Speed= Total distance traveled/total time taken
=40/(1/3+1/2)=40/(5/6)
=48
Manager
Joined: 23 Sep 2016
Posts: 201
Re: A man travels a distance of 20 miles at 60 miles per hour and then re [#permalink]

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03 Mar 2018, 03:44
Bunuel wrote:
A man travels a distance of 20 miles at 60 miles per hour and then returns over the same route at 40 miles per hour. What is his average rate for the round trip in miles per hour?

(A) 50

(B) 48

(C) 47

(D) 46

(E) 45

IMO B
i will show in table which is attached bellow
Attachments

Screenshot (82).png [ 77.13 KiB | Viewed 127 times ]

Re: A man travels a distance of 20 miles at 60 miles per hour and then re   [#permalink] 03 Mar 2018, 03:44
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