GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 21 Feb 2019, 12:04

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

## Events & Promotions

###### Events & Promotions in February
PrevNext
SuMoTuWeThFrSa
272829303112
3456789
10111213141516
17181920212223
242526272812
Open Detailed Calendar

February 21, 2019

February 21, 2019

10:00 PM PST

11:00 PM PST

Kick off your 2019 GMAT prep with a free 7-day boot camp that includes free online lessons, webinars, and a full GMAT course access. Limited for the first 99 registrants! Feb. 21st until the 27th.
• ### Free GMAT RC Webinar

February 23, 2019

February 23, 2019

07:00 AM PST

09:00 AM PST

Learn reading strategies that can help even non-voracious reader to master GMAT RC. Saturday, February 23rd at 7 AM PT

# A marketing firm found that, of 800 computer users surveyed, 280 were

Author Message
TAGS:

### Hide Tags

Manager
Joined: 06 Jul 2013
Posts: 59
Location: United States
GMAT 1: 710 Q48 V40
A marketing firm found that, of 800 computer users surveyed, 280 were  [#permalink]

### Show Tags

Updated on: 05 Jul 2018, 10:19
3
00:00

Difficulty:

55% (hard)

Question Stats:

60% (02:05) correct 40% (02:33) wrong based on 118 sessions

### HideShow timer Statistics

A marketing firm found that, of 800 computer users surveyed, 280 were not familiar with either Website A or Website B, 220 were familiar only with Website A, and for every 3 computer users who were familiar only with Website B, one was familiar with both websites. How many of the 800 computer users were familiar with both websites?

(A) 75
(B) 100
(C) 135
(D) 150
(E) 200

Originally posted by TippingPoint93 on 05 Jul 2018, 09:50.
Last edited by Bunuel on 05 Jul 2018, 10:19, edited 1 time in total.
Math Expert
Joined: 02 Sep 2009
Posts: 53063
Re: A marketing firm found that, of 800 computer users surveyed, 280 were  [#permalink]

### Show Tags

05 Jul 2018, 10:24
TippingPoint93 wrote:
A marketing firm found that, of 800 computer users surveyed, 280 were not familiar with either Website A or Website B, 220 were familiar only with Website A, and for every 3 computer users who were familiar only with Website B, one was familiar with both websites. How many of the 800 computer users were familiar with both websites?

(A) 75
(B) 100
(C) 135
(D) 150
(E) 200

Total = A + B - Both + Neither.

Total = 800
280 were not familiar with either Website A or Website B: Neither = 280
220 were familiar only with Website A: A - Both = 220
For every 3 computer users who were familiar only with Website B, one was familiar with both websites: B - Both = 3*Both --> B = 4*Both.

800 = A + B - Both + 280.
Since A - Both = 220, then 800 = 220 + B + 280.
B =300.

B = 4*Both --> 300 = 4*Both --> Both = 75.

P.S. You have to provide the OA's when posting questions.
_________________
Director
Status: Learning stage
Joined: 01 Oct 2017
Posts: 958
WE: Supply Chain Management (Energy and Utilities)
Re: A marketing firm found that, of 800 computer users surveyed, 280 were  [#permalink]

### Show Tags

05 Jul 2018, 10:54
2
1
TippingPoint93 wrote:
A marketing firm found that, of 800 computer users surveyed, 280 were not familiar with either Website A or Website B, 220 were familiar only with Website A, and for every 3 computer users who were familiar only with Website B, one was familiar with both websites. How many of the 800 computer users were familiar with both websites?

(A) 75
(B) 100
(C) 135
(D) 150
(E) 200

Please refer the affixed Venn diagram,
800 computer users surveyed, T=800
280 were not familiar with either Website A or Website B, n=280
220 were familiar only with Website A, a=220
for every 3 computer users who were familiar only with Website B, one was familiar with both websites; if c=x then b=3x.
Question stem:- c=x=?

We have a+c+b+n=T=800
Or, 220+x+3x+280=800
Or,4x=300
or, x=$$\frac{300}{4}$$=75

Ans. (A)
Attachments

overlapping.JPG [ 21.46 KiB | Viewed 1387 times ]

_________________

Regards,

PKN

Rise above the storm, you will find the sunshine

e-GMAT Representative
Joined: 04 Jan 2015
Posts: 2593
A marketing firm found that, of 800 computer users surveyed, 280 were  [#permalink]

### Show Tags

05 Jul 2018, 22:22
2

Solution

Given:
• Number of computer users surveyed = 800
• Number of users not familiar with either Website A or Website B = 280
• Number of users familiar with only Website A = 220
• For every 3 computer users who were familiar only with Website B, one was familiar with both websites

To find:
• Number of computer users familiar with both the websites

Approach and Working:
• Let us assume,
o Number of users surveyed as U
o Number of users familiar with Website A as A, and
o Number of users familiar with Website B as B
• From the given information,
o U = 800
o U - (A ⋃ B) = 280 => (A ⋃ B) = U - 280 ……………………….. (1)
o A – (A ⋂ B) = 220 => A = 220 + (A ⋂ B) ……………………… (2)
o B - (A ⋂ B) = 3(A ⋂ B) => B = 4(A ⋂ B)………………………………. (3)
• (A ⋃ B) = A + B - (A ⋂ B)
• Substituting (1), (2) and (3) in the above equation, we get
o U - 280 = 220 + (A ⋂ B) + 4(A ⋂ B) - (A ⋂ B)
o Implies, 4(A ⋂ B) = 800 – 280 -220
o Thus, (A ⋂ B) = 300/4 = 75

Therefore, number of computer users familiar with both the websites = 75

Hence, the correct answer is option A.

_________________

| '4 out of Top 5' Instructors on gmatclub | 70 point improvement guarantee | www.e-gmat.com

Intern
Joined: 05 Sep 2016
Posts: 29
Location: India
Concentration: General Management, Operations
WE: Engineering (Energy and Utilities)
Re: A marketing firm found that, of 800 computer users surveyed, 280 were  [#permalink]

### Show Tags

14 Jul 2018, 20:33
PKN wrote:
TippingPoint93 wrote:
A marketing firm found that, of 800 computer users surveyed, 280 were not familiar with either Website A or Website B, 220 were familiar only with Website A, and for every 3 computer users who were familiar only with Website B, one was familiar with both websites. How many of the 800 computer users were familiar with both websites?

(A) 75
(B) 100
(C) 135
(D) 150
(E) 200

Please refer the affixed Venn diagram,
800 computer users surveyed, T=800
280 were not familiar with either Website A or Website B, n=280
220 were familiar only with Website A, a=220
for every 3 computer users who were familiar only with Website B, one was familiar with both websites; if c=x then b=3x.
Question stem:- c=x=?

We have a+c+b+n=T=800
Or, 220+x+3x+280=800
Or,4x=300
or, x=$$\frac{300}{4}$$=75

Ans. (A)

Of the three approaches listed by three users i found yours to be the simplest!!
Manager
Joined: 29 May 2017
Posts: 128
Location: Pakistan
Concentration: Social Entrepreneurship, Sustainability
Re: A marketing firm found that, of 800 computer users surveyed, 280 were  [#permalink]

### Show Tags

25 Jul 2018, 01:37
PKN wrote:
TippingPoint93 wrote:
A marketing firm found that, of 800 computer users surveyed, 280 were not familiar with either Website A or Website B, 220 were familiar only with Website A, and for every 3 computer users who were familiar only with Website B, one was familiar with both websites. How many of the 800 computer users were familiar with both websites?

(A) 75
(B) 100
(C) 135
(D) 150
(E) 200

Please refer the affixed Venn diagram,
800 computer users surveyed, T=800
280 were not familiar with either Website A or Website B, n=280
220 were familiar only with Website A, a=220
for every 3 computer users who were familiar only with Website B, one was familiar with both websites; if c=x then b=3x.
Question stem:- c=x=?

We have a+c+b+n=T=800
Or, 220+x+3x+280=800
Or,4x=300
or, x=$$\frac{300}{4}$$=75

Ans. (A)

I got the answer by the double matrix method but the Venn approach gave me a wrong answer:

the formula is: total grp 1+ grp 2 - both + neither.

why are you using +c and not -c?

thanks
Director
Status: Learning stage
Joined: 01 Oct 2017
Posts: 958
WE: Supply Chain Management (Energy and Utilities)
Re: A marketing firm found that, of 800 computer users surveyed, 280 were  [#permalink]

### Show Tags

25 Jul 2018, 03:18
Mansoor50 wrote:
PKN wrote:
TippingPoint93 wrote:
A marketing firm found that, of 800 computer users surveyed, 280 were not familiar with either Website A or Website B, 220 were familiar only with Website A, and for every 3 computer users who were familiar only with Website B, one was familiar with both websites. How many of the 800 computer users were familiar with both websites?

(A) 75
(B) 100
(C) 135
(D) 150
(E) 200

Please refer the affixed Venn diagram,
800 computer users surveyed, T=800
280 were not familiar with either Website A or Website B, n=280
220 were familiar only with Website A, a=220
for every 3 computer users who were familiar only with Website B, one was familiar with both websites; if c=x then b=3x.
Question stem:- c=x=?

We have a+c+b+n=T=800
Or, 220+x+3x+280=800
Or,4x=300
or, x=$$\frac{300}{4}$$=75

Ans. (A)

I got the answer by the double matrix method but the Venn approach gave me a wrong answer:

the formula is: total grp 1+ grp 2 - both + neither.

why are you using +c and not -c?

thanks

Hi Mansoor50,
Let's apply your formula :-total= grp 1+ grp 2 - both + neither------------(1)
Given total=800, neither=280,
Only groupA=grpA-Both=220
Or, grpA=220+both-------------------------------------------------------------------(2)
Only grpB=grpB-Both
Given,Only grpB=3*both
Or, grpB-Both=3*both
Or, grpB=4*both-----------------------------------------------------------------------(3)
substituting in (1), 800=220+both+4*both-both+280
Or, 800=500+4*both
Or, $$both=\frac{300}{4}=75$$
We have arrived at the solution using your formula and concepts.
(The notations A , B denoted for website A & Website B)

P.S:-
We need to understand the nomenclatures a,b, and c.(As per my approach)
a=only grp1
b=only grp2
c=both grp1 & 2
n=neither grp1 nor grp2
T=Total group
So, Total=only grp1+only grp2+both grp1 & 2+neither grp1 nor grp2----------------(a)

We can transform the above deduction into your formula:-
since grp1=only grp1+both, So, only grp1=grp1-both; now substituting in (a)

Total=only grp1+only grp2+both grp1 & 2+neither grp1 nor grp2
Or, Total=(grp1-both)+(grp2-both)+both+neither
Or, Total=grp1+grp2-2*both+both+neither
Or, Total=grp1+grp2-both+neither-------------------------------------------------------------(b)

So, basically, both the formula and the deduction are the the same. The only difference is method of consideration of "only" or "only+both".

Hope it helps.
_________________

Regards,

PKN

Rise above the storm, you will find the sunshine

Target Test Prep Representative
Affiliations: Target Test Prep
Joined: 04 Mar 2011
Posts: 2827
Re: A marketing firm found that, of 800 computer users surveyed, 280 were  [#permalink]

### Show Tags

26 Jul 2018, 15:29
TippingPoint93 wrote:
A marketing firm found that, of 800 computer users surveyed, 280 were not familiar with either Website A or Website B, 220 were familiar only with Website A, and for every 3 computer users who were familiar only with Website B, one was familiar with both websites. How many of the 800 computer users were familiar with both websites?

(A) 75
(B) 100
(C) 135
(D) 150
(E) 200

Let’s denote the number of users who are familiar with both websites as x. Then, the number of users who are familiar with only website B is 3x.

We can use the formula:

Total = only A + only B + both + neither

800 = 220 + 3x + x + 280

800 = 500 + 4x

300 = 4x

75 = x

_________________

Jeffery Miller

GMAT Quant Self-Study Course
500+ lessons 3000+ practice problems 800+ HD solutions

Director
Status: Come! Fall in Love with Learning!
Joined: 05 Jan 2017
Posts: 542
Location: India
Re: A marketing firm found that, of 800 computer users surveyed, 280 were  [#permalink]

### Show Tags

03 Feb 2019, 21:18
Solution:
The best way to solve the problem is by grid method.
Attachment:

table1.PNG [ 10.23 KiB | Viewed 281 times ]

Let’s fill the grid by the information given the question. 280 were not familiar with either Website A or
Website B, 220 were familiar only with Website A.
For every 3 computer users who were familiar only with Website B, and one was familiar with both
websites.
Let “x” be the number of computer users who are familiar with both the websites and “3x” be the number
of computer users who are familiar with only website B.
Attachment:

table2.PNG [ 11.6 KiB | Viewed 281 times ]

So, from above grid it’s very much clear that;

The number of computer users who are familiar with both the websites = 75.
So, the correct answer option is “A”.
_________________

GMAT Mentors

Manager
Joined: 22 Sep 2018
Posts: 246
Re: A marketing firm found that, of 800 computer users surveyed, 280 were  [#permalink]

### Show Tags

05 Feb 2019, 10:38
TippingPoint93 wrote:
A marketing firm found that, of 800 computer users surveyed, 280 were not familiar with either Website A or Website B, 220 were familiar only with Website A, and for every 3 computer users who were familiar only with Website B, one was familiar with both websites. How many of the 800 computer users were familiar with both websites?

(A) 75
(B) 100
(C) 135
(D) 150
(E) 200

My reasoning if it helps anyone:

Every 3 computer users who were familiar only with Website B, one was familiar with both websites. This means Both : Only Website B is in a ratio of 1:3.

If 280 were not familiar that means (800 - 280) 520 is the total group split between Website A/B/both.

So total = Website A + Website B + Both A&B

Website A = 220

Website B = B

Both A&B = $$B/3$$\frac{[}{fraction]

520 = 220 + B + $$[fraction]B/3}$$

B = 225

Both A&B = 225/3 = 75 (Answer Choice A)
Re: A marketing firm found that, of 800 computer users surveyed, 280 were   [#permalink] 05 Feb 2019, 10:38
Display posts from previous: Sort by