|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Updated on: 25 Jul 2012, 08:33
Originally posted by imhimanshu on 24 Jul 2012, 06:01.
Last edited by Bunuel on 25 Jul 2012, 08:33, edited 1 time in total.
Last edited by Bunuel on 25 Jul 2012, 08:33, edited 1 time in total.
Edited the question.
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
59% (02:10) correct
41%
(02:16)
wrong
based on 881
sessions
History
Date
Time
Result
Not Attempted Yet
A math teacher has 30 cards, each of which is in the shape of a geometric figure. Half of the cards are rectangles, and a third of the cards are rhombuses. If 8 cards are squares, what is the maximum possible number of cards that re circles.
A. 9
B. 10
C. 11
D. 12
E. 13
A. 9
B. 10
C. 11
D. 12
E. 13
24 Jul 2012, 07:16
Kudos
Bookmarks
Remember:
a square is a special kind of rhombus (sides are perpendicular)
a square is a special kind of rectangles (sides with same length)
Among the 30 cards with have:
15 rectangles
10 rhombus
8 squares
Among the 15 rectangles, there could be 8 special ones (with sides of same length) that are squares. That lets at least 7 rectangles that are not square.
Among the 10 rectangles, there could be 8 special ones (with sides perpendicular) that are squares. That lets at least 2 rhombus that are not square.
We have 8 squares.
So the minimum different cards that represent a square, a rhombus or a rectangle is 2 + 7 + 8 = 17
Which means that the maximum number of circles that you could have is 30 - 17 = 13
Answer (E)
a square is a special kind of rhombus (sides are perpendicular)
a square is a special kind of rectangles (sides with same length)
Among the 30 cards with have:
15 rectangles
10 rhombus
8 squares
Among the 15 rectangles, there could be 8 special ones (with sides of same length) that are squares. That lets at least 7 rectangles that are not square.
Among the 10 rectangles, there could be 8 special ones (with sides perpendicular) that are squares. That lets at least 2 rhombus that are not square.
We have 8 squares.
So the minimum different cards that represent a square, a rhombus or a rectangle is 2 + 7 + 8 = 17
Which means that the maximum number of circles that you could have is 30 - 17 = 13
Answer (E)
24 Jul 2012, 07:15
Kudos
Bookmarks
imhimanshu
Squares are both rectangles and rhombuses. Circles are neither rectangles, nor rhombuses.
There are 15 rectangles and 10 rhombuses.
Using a Venn diagram or a 2 X 2 table, we can deduce that the maximum number of cards that re circles is 30 - (15 + 10 - 8) = 13.
Answer: E
