Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 1810:00 AM PDT
-11:00 AM PDT
Join us in a live GMAT practice session and solve 25 challenging GMAT questions with other test takers in timed conditions, covering GMAT Quant, Data Sufficiency, Data Insights, Reading Comprehension, and Critical Reasoning questions.
May 1212:00 PM EDT
-11:59 PM EDT
Make the most of your break with the most realistic GMAT™ prep. Take up to $700 off select products. Ends 6/1
May 1501:00 PM IST
-11:00 AM IST
Start your journey with a fully customized action plan and work with a dedicated mentor to achieve a 735+ score.- May 19
12:00 PM PDT
-01:00 PM PDT
Scoring 329 on the GRE is not always about using more books, more courses, or a longer study plan. In this episode of GRE Success Talks, Ashutosh shares his GRE preparation strategy, study plan, and test-day experience, explaining how he kept his prep.... - Jun 10
06:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
30 Nov 2021, 07:45
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
48% (03:34) correct
52%
(03:22)
wrong
based on 93
sessions
History
Date
Time
Result
Not Attempted Yet
A milkman mixes water and milk in a container in the ratio of 2 : 5, respectively. Initially, he sells the mixture at $30 per liter. After selling 70 liters of mixture, he mixes another 20 liters of water and then ratio of water and milk becomes 8 : 15, respectively. The new mixture is sold by the milk man at the rate of $25 per liter. If cost of milk is $27 per liter then find the profit of milkman in the whole transaction?
A. $2050
B. $2500
C. $2950
D. $2450
E. $3300
A. $2050
B. $2500
C. $2950
D. $2450
E. $3300
Updated on: 30 Dec 2021, 22:54
Originally posted by lovikansal on 12 Dec 2021, 23:33.
Last edited by lovikansal on 30 Dec 2021, 22:54, edited 1 time in total.
Last edited by lovikansal on 30 Dec 2021, 22:54, edited 1 time in total.
Kudos
Bookmarks
Profit before ratio change:
Milk in mixture: 70 * \(\frac{5}{7}\) = 50 L
Therefore, water in mixture = 70 - 50 = 20 L
Profit = (70*30) - (50*27) = $750
Profit after ratio change:
\(\frac{W}{M}\) = \(\frac{2}{5}\)
W= \(\frac{2M}{5}\)
Since, 70L of mixture (of which 50L was milk and 20L was water) was used and 20L of water was added, the new ratio can be written as:
\(\frac{(W - 20 + 20)}{(M -50)}\) = \(\frac{8}{15}\)
15W = 8M - 400,
using, the highlighted equation, substitute the value of W and then solve the equation to get, M= 200
Enter the value of M in: 15W = 8M - 400, to get W= 80
Total Milk and Water = (W + 20 - 20) + (M - 50) = 80 + 150 = 230L
Profit after ratio change: (230*25) - (150*27) = $1700
Total Profit:
$750 + $1700 = $2450
Hence, option D is the correct answer.
Milk in mixture: 70 * \(\frac{5}{7}\) = 50 L
Therefore, water in mixture = 70 - 50 = 20 L
Profit = (70*30) - (50*27) = $750
Profit after ratio change:
\(\frac{W}{M}\) = \(\frac{2}{5}\)
W= \(\frac{2M}{5}\)
Since, 70L of mixture (of which 50L was milk and 20L was water) was used and 20L of water was added, the new ratio can be written as:
\(\frac{(W - 20 + 20)}{(M -50)}\) = \(\frac{8}{15}\)
15W = 8M - 400,
using, the highlighted equation, substitute the value of W and then solve the equation to get, M= 200
Enter the value of M in: 15W = 8M - 400, to get W= 80
Total Milk and Water = (W + 20 - 20) + (M - 50) = 80 + 150 = 230L
Profit after ratio change: (230*25) - (150*27) = $1700
Total Profit:
$750 + $1700 = $2450
Hence, option D is the correct answer.
13 Dec 2021, 08:23
Kudos
Bookmarks
Bunuel
S.P for first 70 litres of mixture = 70*30 = 2100.
Amount of milk in that 70 litres = 50 litres. |2x+5x = 70, x = 10 So, 5x = 50.
C.P for 70 litres of mixture = 50*27 = 1350. |27 rate of milk
Profit from first 70 litres = 2100-1350 = 750.
Now coming to the second part:
after adding 20 litres of water new ratio of milk and water is 15:8
Initial ratio = 5:2
so putting in equation
5x:2x+20 = 15:8
Will give x = 30
So amount of milk = 150 litres.
Total quantity = 150 + 60 + 20 = 230 litres.
S.P for 230 litres of mixture = 230 * 25 |rate given in question stem
C.P for 230 litres = C.P for 150 litres of milk = 150*27
Profit = 230*25 - 150*27
On solving we will get 1700.
Now adding profits from both the transaction = 1700+750 = $2450 which is option D
