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A motorcycle travels at a speed of x kilometers per p hours. How many

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A motorcycle travels at a speed of x kilometers per p hours. How many [#permalink]

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A motorcycle travels at a speed of x kilometers per p hours. How many meters will it travel in s seconds, in terms of s, p and x. (xps ≠ 0; 1 kilometer = 1000 meters)?

A. xp/s
B. 1000xp/s
C. sx/(3.6p)
D. 60xp/s
E. xp3.6*10^s
[Reveal] Spoiler: OA

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Re: A motorcycle travels at a speed of x kilometers per p hours. How many [#permalink]

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New post 18 Nov 2015, 01:42
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Distance travelled = (1000*x) metres
Time taken = s seconds = (p*3600) seconds
Therefore 1 sec = (3600p)/s

Speed in metres/sec = (1000x)/(3600p/s) = (sx/3.6p)

Answer: C
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A motorcycle travels at a speed of x kilometers per p hours. How many [#permalink]

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New post 18 Nov 2015, 02:07
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speed of the motorcycle=x/p Kilometre/hour =x*1000/p*3600 metre/second =10x/36p metre/second
hence in s seconds it would have travelled 10xs/36p = xs/3.6p metres
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Re: A motorcycle travels at a speed of x kilometers per p hours. How many [#permalink]

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New post 18 Nov 2015, 19:37
x/p=kilometers per hour
1000x/3600p=meters per second
(x/3.6p)(s seconds)=sx/3.6p meters
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A motorcycle travels at a speed of x kilometers per p hours. How many [#permalink]

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New post 03 Feb 2018, 03:36
Vyshak wrote:
Distance travelled = (1000*x) metres
Time taken = s seconds = (p*3600) seconds
Therefore 1 sec = (3600p)/s

Speed in metres/sec = (1000x)/(3600p/s) = (sx/3.6p)

Answer: C


Hello niks18 :) its me :)

can you help me to understand why solution to this question isnt this one (1000x)/(p3600) "p" hours are already converted to seconds :? It already exprssed meters per seconds.

so after this Time taken = s seconds = (p*3600) seconds comes this 'Therefore 1 sec = (3600p)/s" does it mean we divide by S ? so S/S gives you 1 second ? Right ? :? and it doesnt imply that if we divide 3600p/s we will have 1 as actual value. So 1 is expressed algebraically right ?

I halways have hard time in applying rule " IN TERMS OF" in this case got confused cause it says in terms of x, s, and p. I got used to expression y in terms of x which means we need to isolate y, and in the above mentioned example we need to isolate all three :?

many thanks and have a great weekend :)
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Re: A motorcycle travels at a speed of x kilometers per p hours. How many [#permalink]

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New post 03 Feb 2018, 04:10
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dave13 wrote:
Vyshak wrote:
Distance travelled = (1000*x) metres
Time taken = s seconds = (p*3600) seconds
Therefore 1 sec = (3600p)/s

Speed in metres/sec = (1000x)/(3600p/s) = (sx/3.6p)

Answer: C


Hello niks18 :) its me :)

can you help me to understand why solution to this question isnt this one (1000x)/(p3600) "p" hours are already converted to seconds :? It already exprssed meters per seconds.

so after this Time taken = s seconds = (p*3600) seconds comes this 'Therefore 1 sec = (3600p)/s" does it mean we divide by S ? so S/S gives you 1 second ? Right ? :? and it doesnt imply that if we divide 3600p/s we will have 1 as actual value. So 1 is expressed algebraically right ?

I halways have hard time in applying rule " IN TERMS OF" in this case got confused cause it says in terms of x, s, and p. I got used to expression y in terms of x which means we need to isolate y, and in the above mentioned example we need to isolate all three :?

many thanks and have a great weekend :)


Hi dave13

\(s\) is a variable here so you cannot cancel \(s\) by S from "Sec". instead of s there could have been any other notation such as t, a, b etc.

Alternatively we know Speed = \(\frac{x}{p}\) \(\frac{km}{h}\) \(= \frac{1000*x}{3600p}\) \(\frac{m}{sec}\)

time \(= s\) seconds

Distance \(= Speed*time=\frac{1000*x}{3500p}*s\)

Another approach, as the have only variable here so let x=1 km, p=1 hour & s=1 sec

so as per question speed = 1/1 kmph=1000/36000 m/sec=1/3.6 m/sec

Hence distance traveled in 1 sec = 1/3.6*1=1/3.6

Now substitute the value of x, p & s in option to arrive at the answer

For Option C= sx/3.6p=1*!/3.6*1=1/3.6, Hence our answer
Re: A motorcycle travels at a speed of x kilometers per p hours. How many   [#permalink] 03 Feb 2018, 04:10
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