dave13 wrote:
Vyshak wrote:
Distance travelled = (1000*x) metres
Time taken = s seconds = (p*3600) seconds
Therefore 1 sec = (3600p)/s
Speed in metres/sec = (1000x)/(3600p/s) = (sx/3.6p)
Answer: C
Hello
niks18 its me
can you help me to understand why solution to this question isnt this one (1000x)/(p3600) "p" hours are already converted to seconds
It already exprssed meters per seconds.
so after this
Time taken = s seconds = (p*3600) seconds comes this '
Therefore 1 sec = (3600p)/s" does it mean we divide by S ? so S/S gives
you 1 second ? Right ?
and it doesnt imply that if we divide 3600p/s we will have 1 as actual value. So 1 is expressed algebraically right ?
I halways have hard time in applying rule " IN TERMS OF" in this case got confused cause it says in terms of x, s, and p. I got used to expression y in terms of x which means we need to isolate y, and in the above mentioned example we need to isolate all three
many thanks and have a great weekend
Hi
dave13\(s\) is a variable here so you cannot cancel \(s\) by S from "Sec". instead of s there could have been any other notation such as t, a, b etc.
Alternatively we know Speed = \(\frac{x}{p}\) \(\frac{km}{h}\) \(= \frac{1000*x}{3600p}\) \(\frac{m}{sec}\)
time \(= s\) seconds
Distance \(= Speed*time=\frac{1000*x}{3500p}*s\)
Another approach, as the have only variable here so let x=1 km, p=1 hour & s=1 sec
so as per question speed = 1/1 kmph=1000/36000 m/sec=1/3.6 m/sec
Hence distance traveled in 1 sec = 1/3.6*1=1/3.6
Now substitute the value of x, p & s in option to arrive at the answer
For Option C= sx/3.6p=1*!/3.6*1=1/3.6, Hence our answer