dave13 wrote:

Vyshak wrote:

Distance travelled = (1000*x) metres

Time taken = s seconds = (p*3600) seconds

Therefore 1 sec = (3600p)/s

Speed in metres/sec = (1000x)/(3600p/s) = (sx/3.6p)

Answer: C

Hello

niks18 its me

can you help me to understand why solution to this question isnt this one (1000x)/(p3600) "p" hours are already converted to seconds

It already exprssed meters per seconds.

so after this

Time taken = s seconds = (p*3600) seconds comes this '

Therefore 1 sec = (3600p)/s" does it mean we divide by S ? so S/S gives

you 1 second ? Right ?

and it doesnt imply that if we divide 3600p/s we will have 1 as actual value. So 1 is expressed algebraically right ?

I halways have hard time in applying rule " IN TERMS OF" in this case got confused cause it says in terms of x, s, and p. I got used to expression y in terms of x which means we need to isolate y, and in the above mentioned example we need to isolate all three

many thanks and have a great weekend

Hi

dave13\(s\) is a variable here so you cannot cancel \(s\) by S from "Sec". instead of s there could have been any other notation such as t, a, b etc.

Alternatively we know Speed = \(\frac{x}{p}\) \(\frac{km}{h}\) \(= \frac{1000*x}{3600p}\) \(\frac{m}{sec}\)

time \(= s\) seconds

Distance \(= Speed*time=\frac{1000*x}{3500p}*s\)

Another approach, as the have only variable here so let x=1 km, p=1 hour & s=1 sec

so as per question speed = 1/1 kmph=1000/36000 m/sec=1/3.6 m/sec

Hence distance traveled in 1 sec = 1/3.6*1=1/3.6

Now substitute the value of x, p & s in option to arrive at the answer

For Option C= sx/3.6p=1*!/3.6*1=1/3.6, Hence our answer