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19 Aug 2008, 08:22
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a painter calculated the amount of paint needed to cover the four wall of a window less room, but mistakenly assumed that the walls were 9ft tall when they were in fact 10ft tall. his initial calcualtion indicated that he would need 18 cans of paint. If each can of paint can cover an area of 25 square feet, what is the actual number of cans needed to paint the room?
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19 Aug 2008, 08:34
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pattydread
Initial calc = 25*18 = 450sq ft
Let x be width of one wall and y of other.
9x + 9y + 9x + 9y = 18 (x + y) = 450
x + y = 25
When height = 10
Area = 25*10*2 = 500
Therefore cans required = 20
19 Aug 2008, 09:59
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let x is the width of wall.
So for the 9 ft tall wall, the area is 9x and he would need 18 cans of paint
If the actual length is 10 ft then for 10x he would need 18/9x*10= 20 can of paint
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a painter calculated the amount of paint needed to cover the four wall of a window less room, but mistakenly assumed that the walls were 9ft tall when they were in fact 10ft tall. his initial calcualtion indicated that he would need 18 cans of paint. If each can of paint can cover an area of 25 square feet, what is the actual number of cans needed to paint the room?
So for the 9 ft tall wall, the area is 9x and he would need 18 cans of paint
If the actual length is 10 ft then for 10x he would need 18/9x*10= 20 can of paint
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a painter calculated the amount of paint needed to cover the four wall of a window less room, but mistakenly assumed that the walls were 9ft tall when they were in fact 10ft tall. his initial calcualtion indicated that he would need 18 cans of paint. If each can of paint can cover an area of 25 square feet, what is the actual number of cans needed to paint the room?
