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# a painter calculated the amount of paint needed to cover the

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Intern
Joined: 05 Aug 2008
Posts: 13
a painter calculated the amount of paint needed to cover the [#permalink]

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19 Aug 2008, 08:22
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a painter calculated the amount of paint needed to cover the four wall of a window less room, but mistakenly assumed that the walls were 9ft tall when they were in fact 10ft tall. his initial calcualtion indicated that he would need 18 cans of paint. If each can of paint can cover an area of 25 square feet, what is the actual number of cans needed to paint the room?

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Senior Manager
Joined: 06 Apr 2008
Posts: 401

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19 Aug 2008, 08:34
a painter calculated the amount of paint needed to cover the four wall of a window less room, but mistakenly assumed that the walls were 9ft tall when they were in fact 10ft tall. his initial calcualtion indicated that he would need 18 cans of paint. If each can of paint can cover an area of 25 square feet, what is the actual number of cans needed to paint the room?

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Initial calc = 25*18 = 450sq ft

Let x be width of one wall and y of other.

9x + 9y + 9x + 9y = 18 (x + y) = 450
x + y = 25

When height = 10

Area = 25*10*2 = 500

Therefore cans required = 20
Manager
Joined: 11 Apr 2008
Posts: 198

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19 Aug 2008, 09:59
let x is the width of wall.
So for the 9 ft tall wall, the area is 9x and he would need 18 cans of paint
If the actual length is 10 ft then for 10x he would need 18/9x*10= 20 can of paint

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a painter calculated the amount of paint needed to cover the four wall of a window less room, but mistakenly assumed that the walls were 9ft tall when they were in fact 10ft tall. his initial calcualtion indicated that he would need 18 cans of paint. If each can of paint can cover an area of 25 square feet, what is the actual number of cans needed to paint the room?
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Senior Manager
Joined: 19 Mar 2008
Posts: 350

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19 Aug 2008, 10:47
a painter calculated the amount of paint needed to cover the four wall of a window less room, but mistakenly assumed that the walls were 9ft tall when they were in fact 10ft tall. his initial calcualtion indicated that he would need 18 cans of paint. If each can of paint can cover an area of 25 square feet, what is the actual number of cans needed to paint the room?

Assme the perimeter of the room is x
y is the actual required no. of can

9x=18*25
x = 50 sq feet

actual total area = 50*10 = 500
y = 500/25 = 20
Re: area   [#permalink] 19 Aug 2008, 10:47
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# a painter calculated the amount of paint needed to cover the

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