The probability that the sum of the numbers rolled is 12 If a pair is rolled then we will have two values and their sum is 12.
Only favorable outcome is (6,6) [ 6 in both of them ]
Total Number of outcomes = \(6^2\) = 36
So, The probability that the sum of the numbers rolled is 12 =\( \frac{favorable Outcomes}{total Outcomes}\) =\(\frac{ 1}{ 36}\)
The probability that the sum is 2Only favorable outcome is (1,1) [ 1 in both of them ]
Total Number of outcomes = \(6^2\) = 36
So, The probability that the sum of the numbers rolled is 2 =\( \frac{favorable Outcomes}{total Outcomes}\) =\(\frac{ 1}{ 36}\)
Since both are same so The probability that the sum of the numbers rolled is 12 is what percent greater than the probability that the sum is 2 will be 0%
So,
Answer will be AHope it helps!
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