shridhar786
A pianist is planning the order in which they will play their recital. They will play 6 pieces by 6 different composers: Brahms, Chopin, Haydn, Liszt, Mozart, and Schubert. The recital will be in two halves with 3 pieces before a short interval and 3 pieces straight after. The pianist decides that the final piece in each half will be by one of Liszt, Brahms, or Mozart. How many different possible orders are there for the pianist’s recital?
a) 48
b) 72
c) 120
d)144
e) 720
Solution:
The ordering of the musical recital is ___, ___, ___, interval, ___, ___, ___
We see that positions 3 and 6 can be filled by any of 3 composers, so for just those two positions, we have 3P2 = 6 ways to fill them. For the remaining positions (1, 2, 4, and 5), we have 4! = 24 ways to arrange them. Thus, the total number of arrangements of the selections for the recital is 3P2 x 4! = 6 x 24 = 144.
Answer: D